Problem 31
Question
Find an expression for \(a_{n}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, \ldots\) \(-1,2,-3,4,-5, \ldots\)
Step-by-Step Solution
Verified Answer
\(a_n = (-1)^n (n + 1)\).
1Step 1: Look for a pattern
Examine the given sequence: \(-1, 2, -3, 4, -5, \ldots\). Notice that the sequence alternates between negative and positive numbers, and the absolute value of each term increases linearly, matching the sequence of natural numbers: 1, 2, 3, 4, 5,...
2Step 2: Determine the sign pattern
The sequence has a sign pattern: the signs alternate starting with negative for \(a_0\), positive for \(a_1\), negative for \(a_2\), etc. This alternating sign can be represented by \((-1)^n\), since \((-1)^n\) results in -1 for even \(n\) and 1 for odd \(n\).
3Step 3: Determine the magnitude pattern
The magnitude of each term increases as the sequence of natural numbers: 1, 2, 3, 4, 5,.... Thus, for each \(a_n\), the magnitude matches \(n + 1\).
4Step 4: Combine sign and magnitude to form the general formula
Combine the results from Steps 2 and 3. The general term for the sequence is given by the product of the alternating sign and the magnitude sequence: \(a_n = (-1)^n (n + 1)\). This formula will generate the sequence: \(-1\) for \(n=0\), \(2\) for \(n=1\), \(-3\) for \(n=2\), etc.
Key Concepts
Alternating SequenceSequence PatternGeneral Term Formula
Alternating Sequence
An alternating sequence is a sequence in which the signs of the terms alternate between positive and negative. In the original exercise, the sequence
-1, 2, -3, 4, -5, ...
illustrates this concept perfectly. Here we see positive numbers are followed by negative numbers and vice versa in a regular pattern. This alternating pattern is fundamental because it shows how the sequence can toggle signs, creating a distinctive oscillating pattern that can often be described mathematically.
Understanding this alternating pattern allows us to use mathematical tools such as
(-1)^n
to succinctly represent the sequence's alternating property. Where the term is negative, like for even indexed terms,
(-1)^n
equals -1, and for odd indexed terms, it equals 1. This mathematical representation is crucial for finding a formula for the general term of the sequence.
Sequence Pattern
The pattern within a sequence refers to the consistent, predictable rule that defines how terms are arranged. Recognizing the sequence pattern is key to understanding both the sign and the magnitude of terms in sequences such as
-1, 2, -3, 4, -5, ...
In our case, the absolute value of each term in the sequence mirrors the sequence of natural numbers:
- For a_0 , the value is 1 ,
- For a_1 , the value is 2 ,
- For a_2 , the value is 3 ,
General Term Formula
The general term formula in a sequence provides a way to calculate any term in the sequence without having to list all preceding terms. It essentially acts as an efficient shortcut.In the provided exercise, our task is to combine the insights from recognizing the alternating and magnitude patterns. This results in the general term formula:\[a_n = (-1)^n (n + 1)\]Here's how it works:
- The (-1)^n defines the alternating sign.
- The (n + 1) describes the sequence's magnitude, aligned with natural numbers.
Other exercises in this chapter
Problem 30
Find an expression for \(a_{n}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, \ldots\) \(\frac{1}{3}, \frac{2}{5}, \frac{3}{7}, \frac{4}{9}, \frac{5}{11
View solution Problem 30
\mathrm{\\{} I n ~ P r o b l e m s ~ , ~ g r a p h ~ t h e ~ f u n c t i o n s ~ \(f(x)=a^{x}, x \in[0, \infty)\), \mathrm{\\{} a n d ~ \(N_{t}=R^{t}, t \in \ma
View solution Problem 31
In Problems 31-42, find the population sizes for \(t=0,1\), 2, \(\ldots, 5\) for each recursion. Then write the equation for \(N_{t}\) as a function of \(t\). $
View solution Problem 32
Find an expression for \(a_{n}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, \ldots\) \(9,16,25,36,49\)
View solution