Problem 31
Question
Find an equation for the hyperbola that satisfies the given conditions. Foci: \(( \pm 5,0),\) vertices: \(( \pm 3,0)\)
Step-by-Step Solution
Verified Answer
The equation of the hyperbola is \(\frac{x^2}{9} - \frac{y^2}{16} = 1\).
1Step 1: Identify the Center and Orientation
Since the foci are \(( \pm 5,0)\) and the vertices are \(( \pm 3,0)\), the hyperbola is centered at the origin and is oriented horizontally because the x-coordinates of the vertices and foci are non-zero while the y-coordinates are zero.
2Step 2: Determine the Values of a and c
The distance from the center to each vertex is \(|\pm 3 - 0| = 3\). Thus, \(a = 3\). The distance from the center to each focus is \(|\pm 5 - 0| = 5\). Thus, \(c = 5\).
3Step 3: Calculate the Value of b
For a hyperbola, the relationship between \(a\), \(b\), and \(c\) is given by the equation \(c^2 = a^2 + b^2\). Substitute the known values: \(5^2 = 3^2 + b^2\). This simplifies to \(25 = 9 + b^2\). Therefore, \(b^2 = 16\) and \(b = 4\).
4Step 4: Write the Equation of the Hyperbola
The standard form of the equation for a hyperbola with a horizontal transverse axis is \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\). Substitute \(a = 3\) and \(b = 4\) into the equation: \(\frac{x^2}{9} - \frac{y^2}{16} = 1\).
Key Concepts
Conic SectionsFoci and VerticesStandard Form of a HyperbolaValues of a, b, and c
Conic Sections
Conic sections are shapes created by the intersection of a plane with a cone. Depending on the angle and position of the intersection, we can derive different forms:
- Circle - When the intersection is perpendicular to the cone's axis.
- Ellipse - When the intersection is at an angle, but does not pass through the base.
- Parabola - When the plane is parallel to a generating line of the cone.
- Hyperbola - When the plane intersects both halves of the cone.
Foci and Vertices
The foci and vertices are key points in a hyperbola that help us determine its shape and position.
- The foci are two fixed points located such that the difference of the distances from any point on the hyperbola to these foci is a constant. In this case, the foci are \(( \pm 5,0)\), meaning they are located at 5 units on either side of the origin along the x-axis.
- The vertices are points where each branch of the hyperbola is closest to each other. The given vertices are \((\pm 3,0)\), indicating that they are positioned at 3 units on either side of the origin.
Standard Form of a Hyperbola
The standard form of a hyperbola's equation depends on its orientation:
- Horizontal orientation has the form \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \). For our given problem, the x-coordinates of the foci and vertices confirm that the hyperbola is horizontal. This form is used when the transverse axis is along the x-axis.
- Vertical orientation is expressed as \( \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \). This form is used when the transverse axis is along the y-axis.
Values of a, b, and c
The values of \(a\), \(b\), and \(c\) are integral to defining a hyperbola:
- \(a\) - Represents the distance from the center to each vertex along the transverse axis. For our hyperbola, \(a = 3\), as derived from the distance from the center (0,0) to the vertices (\(\pm 3,0\)).
- \(c\) - Indicates the distance from the center to each focus. Here, \(c = 5\), matching the distance from the center to the foci (\(\pm 5,0\)).
- \(b\) - Calculated using the relationship \(c^2 = a^2 + b^2\). For this hyperbola, solving \(25 = 9 + b^2\) tells us that \(b = 4\).
Other exercises in this chapter
Problem 30
Use a graphing device to graph the ellipse. $$ x^{2}+\frac{y^{2}}{12}=1 $$
View solution Problem 30
\(29-40\) Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Focus: \(F\left(0,-\frac{1}{2}\right)\)
View solution Problem 31
(a) Find the eccentricity and identify the conic. (b) Sketch the conic and label the vertices. $$ r=\frac{2}{1-\cos \theta} $$
View solution Problem 31
\(23-34\) Complete the square to determine whether the equation represents an ellipse, a parabola, a hyperbola, or a degenerate conic. If the graph is an ellips
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