Problem 30
Question
\(29-40\) Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Focus: \(F\left(0,-\frac{1}{2}\right)\)
Step-by-Step Solution
Verified Answer
The equation of the parabola is \( x^2 = -2y \).
1Step 1: Understanding the Relation between Vertex, Focus, and Parabola
For a parabola with its vertex at the origin (0,0), the equation of a parabola can be expressed in the form \[ x^2 = 4py \]where the focus is given as \( F(0, p) \). In the given problem, the focus is \( F\left(0, -\frac{1}{2}\right) \). Thus, \( p = -\frac{1}{2} \).
2Step 2: Substitute the Focus into Parabola Equation
Given the focus \( p = -\frac{1}{2} \), substitute \( p \) in the standard form equation of a parabola:\[ x^2 = 4py \]Therefore, substituting the value of \( p \), we have:\[ x^2 = 4(-\frac{1}{2})y \]
3Step 3: Simplify the Equation
Simplify the equation derived:\[ x^2 = 4 \times -\frac{1}{2} \times y \]\[ x^2 = -2y \]This is the equation of the parabola with the vertex at the origin and focus at \( (0, -\frac{1}{2}) \).
Key Concepts
Vertex of a ParabolaFocus of a ParabolaStandard Form of a Parabola
Vertex of a Parabola
The vertex of a parabola is a crucial concept in understanding the overall shape and orientation of the curve. In simple terms, the vertex is the point where the parabola changes direction. For parabolas that open upwards or downwards, this point represents the minimum or maximum height of the curve, respectively.
When the vertex is at the origin,
When the vertex is at the origin,
- The vertex coordinates are (0, 0).
- It simplifies the equation of the parabola since the terms involving the vertex's position drop out.
- The horizontal and vertical shifts (h, k) are zero.
- The parabola's axis of symmetry will go through the origin.
Focus of a Parabola
The focus of a parabola is a fixed point used to define the curve more precisely. It is important in helping determine how the parabola opens and how it behaves.
Key characteristics of the focus include:
Key characteristics of the focus include:
- The distance from the vertex determines the parabola's width and the direction it opens.
- A parabola will always "open" towards its focus (upward, downward, left, or right).
- If the focus is at \( F(0, p) \), then the parabola opens upwards or downwards.
- If the focus is at \( F(p, 0) \), then the parabola opens left or right.
- The parabola opens downward because \( p < 0 \).
- The equation will take the form \[ x^2 = 4py \].
Standard Form of a Parabola
The standard form of a parabola's equation is used to make calculations simple and the graph easy to visualize. The general forms are:
- \[ x^2 = 4py \] for a parabola that opens vertically.
- \[ y^2 = 4px \] for one that opens horizontally.
- \( p \)ds the distance between the vertex and the focus.
- "4p" indicates how stretched or compressed the parabola is.
- The parabola opens downward, as the negative sign indicates.
- The vertex is at the origin (0,0), simplifying graph plotting.
Other exercises in this chapter
Problem 30
\(29-32\) . (a) Use the discriminant to identify the conic. (b) Confirm your answer by graphing the conic using a graphing device. $$ x^{2}-2 x y+3 y^{2}=8 $$
View solution Problem 30
Use a graphing device to graph the ellipse. $$ x^{2}+\frac{y^{2}}{12}=1 $$
View solution Problem 31
Find an equation for the hyperbola that satisfies the given conditions. Foci: \(( \pm 5,0),\) vertices: \(( \pm 3,0)\)
View solution Problem 31
(a) Find the eccentricity and identify the conic. (b) Sketch the conic and label the vertices. $$ r=\frac{2}{1-\cos \theta} $$
View solution