Problem 30
Question
Write an equation of each line. Write the equation in the form \(x=a, y=b\), or \(y=m x+b\). See Examples 5 and \(6 .\) Through (-2,6)\(;\) perpendicular to \(y=7\)
Step-by-Step Solution
Verified Answer
The equation of the line is \(x = -2\).
1Step 1: Understand Line Characteristics
The given line is represented by the equation \(y = 7\), which is a horizontal line. All horizontal lines have a slope of 0.
2Step 2: Identify the Slope of Perpendicular Line
Lines that are perpendicular to horizontal lines are vertical lines. Vertical lines have an undefined slope and are written in the form \(x = a\), where \(a\) is the x-coordinate of any point on the line.
3Step 3: Formulate the Equation of the Perpendicular Line
Since the line must pass through the point (-2, 6) and be perpendicular to \(y = 7\), it must be vertical and take the form \(x = -2\).
4Step 4: Verify the Line Equation
Check that the line \(x = -2\) passes through the point (-2, 6). Since the x-coordinate of the line and the point are the same, the line indeed passes through (-2, 6).
Key Concepts
Perpendicular LinesVertical LinesSlope
Perpendicular Lines
Perpendicular lines are quite special in geometry and algebra. They intersect at a right angle, which is 90 degrees. This relationship between lines involves their slopes. If one line is horizontal, the perpendicular line will be vertical, and vice versa.
So, when asked to find a line that is perpendicular to another, always think about their intersecting nature and their slopes.
- Horizontal lines have a slope of 0.
- Vertical lines have an undefined slope.
So, when asked to find a line that is perpendicular to another, always think about their intersecting nature and their slopes.
Vertical Lines
Vertical lines run straight up and down. They have a distinct characteristic in that their slope is undefined. This happens because slope is calculated with the formula \( m = \frac{\Delta y}{\Delta x} \), and for vertical lines, \( \Delta x = 0 \). Division by zero is undefined, which gives these lines their unique property.
Vertical lines are expressed in the form \( x = a \), where \( a \) is the x-coordinate through which the line passes. Since it never moves horizontally, its x-value remains constant no matter what point on the line you examine.
For example, a vertical line passing through the point \((-2, 6)\) will simply be \( x = -2 \). It doesn’t matter what the y-coordinate is. So anytime you're dealing with a perpendicular line to a horizontal one, it's this concept of vertical lines that comes into play.
Vertical lines are expressed in the form \( x = a \), where \( a \) is the x-coordinate through which the line passes. Since it never moves horizontally, its x-value remains constant no matter what point on the line you examine.
For example, a vertical line passing through the point \((-2, 6)\) will simply be \( x = -2 \). It doesn’t matter what the y-coordinate is. So anytime you're dealing with a perpendicular line to a horizontal one, it's this concept of vertical lines that comes into play.
Slope
The slope of a line is a critical concept in geometry. It's a measure of how steep the line is. Calculated by the formula \( m = \frac{\Delta y}{\Delta x} \), the slope tells us the change in \( y \) (vertical) against the change in \( x \) (horizontal).
- Positive slopes rise as you move from left to right.
- Negative slopes fall as you move from left to right.
- A slope of 0 indicates a horizontal line.
Other exercises in this chapter
Problem 30
If \(f(x)=\frac{x+8}{2 x-1}\) and \(g(x)=\frac{x-2}{x-5},\) find each function value. Find the domain of \(f(x)\).
View solution Problem 30
Sketch the graph of each function. $$ g(x)=-|x+1|+1 $$
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Graph each piecewise-defined function. $$ f(x)=\left\\{\begin{array}{ll} 5 x+4 & \text { if } x \leq 0 \\ \frac{1}{3} x-1 & \text { if } x>0 \end{array}\right.
View solution Problem 31
If \(f(x)=\frac{x^{2}+5}{x}\) and \(g(x)=\frac{x^{2}+2 x}{x+3},\) find each function value. $$ f(1) $$
View solution