Problem 30
Question
Make the required change in the given equation. \(\rho \sin \phi=1\) to Cartesian coordinates
Step-by-Step Solution
Verified Answer
The equation in Cartesian coordinates is \(y = 1\).
1Step 1: Identify the Conversion Formulas
When converting from cylindrical ( \(\rho, \phi\) ) to Cartesian coordinates (\(x, y\)), we use the following relations:\[ x = \rho \cos \phi \]\[ y = \rho \sin \phi \]
2Step 2: Substitute the Expression for \(y\)
Given that \(\rho \sin \phi = 1\), we can substitute the equation in terms of \(y\) since \(y = \rho \sin \phi\). Thus the equation becomes:\[ y = 1 \]
3Step 3: Write the Equation in Cartesian Coordinates
Since we have determined that \(y = 1\), and there is no restriction on \(x\), the equation in Cartesian coordinates is simply:\[ y = 1 \]
Key Concepts
Cylindrical CoordinatesCoordinate ConversionEquation Transformation
Cylindrical Coordinates
Cylindrical coordinates are particularly useful in situations where there is symmetry around an axis, much like polar coordinates but extendable into three dimensions. They are expressed as \((\rho, \phi, z)\), where:
- \(\rho\) represents the radial distance from the origin to the point in the \(xy\)-plane.
- \(\phi\) is the angular coordinate, often measured from the positive x-axis.
- \(z\) is the height or elevation above the \(xy\)-plane.
Coordinate Conversion
Coordinate conversion is a key mathematical process that involves changing from one coordinate system to another. For example, converting from cylindrical coordinates \((\rho, \phi)\) to Cartesian coordinates \((x, y)\), we use the equations:
- \(x = \rho \cos \phi\)
- \(y = \rho \sin \phi\)
Equation Transformation
Equation transformation is the process of rewriting an equation in one coordinate system into an equivalent form in another. This is necessary when working with different mathematical models or when simplifying complex equations.In the given exercise, the equation \(\rho \sin \phi = 1\) was transformed from cylindrical to Cartesian coordinates using the relationship \(y = \rho \sin \phi\). By substituting \(\rho \sin \phi = 1\) with \(y = 1\), the transformation resulted in \(y = 1\) in Cartesian coordinates.Such transformations are vital for analysis and visualization, making them indispensable in applied mathematics and engineering. They help in understanding the geometry and shape of plots in various simulated or real-world models. By practicing equation transformations, one can gain deeper insights into the structure and implications of mathematical models.
Other exercises in this chapter
Problem 30
Find the equation of the surface that results when the curve \(4 x^{2}-3 y^{2}=12\) in the \(x y\) -plane is revolved about the \(x\) -axis.
View solution Problem 30
Find the velocity \(\mathbf{v}\), acceleration \(\mathbf{a}\), and speed \(s\) at the indicated time \(t=t_{1}\). $$ \mathbf{r}(t)=\ln t \mathbf{i}+\ln t^{2} \m
View solution Problem 30
, find the curvature \(\kappa\), the unit tangent vector \(\mathbf{T}\), the unit normal vector \(\mathbf{N}\), and the binormal vector \(\mathbf{B}\) at \(t=t_
View solution Problem 30
Let \(P\) be a point on a plane with normal vector \(\mathbf{n}\) and \(Q\) be a point off the plane. Show that the result of Example 10 of Section \(11.3\), th
View solution