Problem 30
Question
An autocatalytic reaction uses its resulting product for the formation of a new product, as in the reaction $$ \mathrm{A}+\mathrm{X} \rightarrow \mathrm{X} $$ If we assume that this reaction occurs in a closed vessel, then the reaction rate is given by $$ R(x)=k x(a-x) $$ for \(0 \leq x \leq a\), where \(a\) is the initial concentration of \(A\) and \(x\) is the concentration of \(X\). (a) Show that \(R(x)\) is a polynomial and determine its degree. (b) Graph \(R(x)\) for \(k=2\) and \(a=6\). Find the value of \(x\) at which the reaction rate is maximal.
Step-by-Step Solution
Verified Answer
(a) \( R(x) \) is a quadratic polynomial of degree 2. (b) The reaction rate is maximal at \( x = 3 \).
1Step 1: Analyze the Reaction Rate Expression
Consider the reaction rate expression \( R(x) = kx(a-x) \). Expand it to check if it's a polynomial: \[ R(x) = k(ax - x^2) = kax - kx^2. \] This shows \( R(x) \) is a polynomial in \( x \), specifically a quadratic polynomial because the highest power of \( x \) is 2.
2Step 2: Determine the Degree of the Polynomial
Since the expression for \( R(x) = kax - kx^2 \) has the highest power of \( x \) being 2, the degree of the polynomial is 2.
3Step 3: Set up the Graph with Given Values
Substitute \( k = 2 \) and \( a = 6 \) into the equation: \[ R(x) = 2x(6-x) = 12x - 2x^2. \] This will help in graphing the polynomial function to observe its behavior and find the maximum.
4Step 4: Find the Maximum Reaction Rate Using Calculus
The maximum value of \( R(x) \) can be found by taking the derivative: \( R'(x) = \frac{d}{dx}(12x - 2x^2) = 12 - 4x. \) Set \( R'(x) = 0 \) to find the critical points: \[ 12 - 4x = 0 \rightarrow x = 3. \] Check if it's a maximum by evaluating the second derivative, \( R''(x) = -4 \), which is negative, confirming a maximum at \( x = 3 \).
5Step 5: Graph the Reaction Rate Function
Plot the function \( R(x) = 12x - 2x^2 \) using the range \( 0 \leq x \leq 6 \). Observe that the curve is a downward-opening parabola peaking at \( x = 3 \), where the maximum reaction rate occurs.
Key Concepts
Reaction RatePolynomial DegreeQuadratic PolynomialMaximum Reaction Rate
Reaction Rate
The term **reaction rate** refers to how quickly a chemical reaction proceeds over time. In the case of the autocatalytic reaction described, it can be expressed by the equation: \[ R(x) = kx(a-x) \] where:
- \( R(x) \) is the reaction rate.
- \( k \) represents the rate constant.
- \( x \) is the concentration of product \( X \).
- \( a \) is the initial concentration of reactant \( A \).
Polynomial Degree
In mathematics, the **degree of a polynomial** indicates the highest exponent of its variable. For the reaction rate equation \( R(x) = kx(a-x) \), we can expand it to its polynomial form: \[ R(x) = k(ax - x^2) = kax - kx^2 \] The polynomial is expressed in terms of \( x \), and its highest power is 2. This reveals that the polynomial degree is 2, classifying it as a quadratic polynomial. Identifying the degree of a polynomial is crucial as it informs us about the graph's shape—to be more specific, the number of roots and the general behavior of the curve.
Quadratic Polynomial
A **quadratic polynomial** is a second-degree polynomial, typically represented as \( ax^2 + bx + c \). In the context of the reaction, after expanding \( R(x) = kx(a-x) \), we obtain: \[ R(x) = kax - kx^2 \] This is a quadratic with the following components:
- Leading term \( -kx^2 \): Determines the parabola's opening direction.
- Linear term \( kax \): Affects the slope and incline.
- Constant term: In this case, it is zero, simplifying the graph to intersect the origin.
Maximum Reaction Rate
To find the **maximum reaction rate**, we use calculus to determine where the reaction rate peaks. For the equation \( R(x) = 12x - 2x^2 \), we calculate its derivative, \( R'(x) \), to find the rate of change of \( R(x) \): \[ R'(x) = \frac{d}{dx} (12x - 2x^2) = 12 - 4x \] Set \( R'(x) = 0 \) to find critical points, yielding \( x = 3 \). This value indicates where \( R(x) \) might have a maximum or minimum. We confirm a maximum via the second derivative, \( R''(x) = -4 \), which is negative, signifying a peak. This peak suggests the system reaches its highest rate of reaction at \( x = 3 \). Recognizing this maximum is crucial for optimizing reaction conditions in industrial and laboratory settings, as it informs scientists and engineers about the most efficient operational parameters.
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