Problem 3
Question
Let \(m\) be a positive integer. Show that for every real number \(x \geq 1\), the number of multiples of \(m\) in the interval \([1, x]\) is \(\lfloor x / m\rfloor ;\) in particular, for every integer \(n \geq 1,\) the number of multiples of \(m\) among \(1, \ldots, n\) is \(\lfloor n / m\rfloor\).
Step-by-Step Solution
Verified Answer
Answer: The formula to find the number of multiples of a positive integer m in the interval [1, x] for all real numbers x >= 1 is \(\lfloor x/m \rfloor\), and for all integers n >= 1 the formula is \(\lfloor n/m \rfloor\).
1Step 1: Determine the interval of multiples of m
The real number x is given, and we want to find the range of numbers which are multiples of m within the interval [1, x]. Since x is greater than or equal to 1, the smallest multiple of m in the interval would be m itself. The highest multiple of m in the interval would be equal to the product of m and the greatest integer less than or equal to x/m (which we will prove later), that is: m * \(\lfloor x/m \rfloor\).
2Step 2: Define the multiple count
To count the number of multiples of m in the given interval, let's define the multiple count for a given real number x and a positive integer m as:
Multiple count = number of multiples of m in the interval [1, x].
3Step 3: Find the number of multiples within the interval
We want to find a way to express the multiple count in terms of x and m.
If we divide the largest multiple of m within the interval (m * \(\lfloor x/m \rfloor\)) by m, we will obtain the greatest integer less than or equal to x/m:
\(\frac{m * \lfloor x/m \rfloor }{m}\) = \(\lfloor x/m \rfloor\).
Now, we can say that the multiple count is equal to the proportion of the largest multiple of m within the interval to the size of m. So, the multiple count can be written as:
Multiple count = \(\lfloor x/m \rfloor\).
4Step 4: Applying the result to integers n >= 1
We have proven that the number of multiples of m in the interval [1, x] is \(\lfloor x/m \rfloor\) for all real numbers x >= 1. The same result holds for every integer n >= 1 because integers are a subset of real numbers, therefore, Multiple count = \(\lfloor n/m \rfloor\).
Thus, the number of multiples of m in the interval [1, x] for all x >= 1 is \(\lfloor x/m \rfloor\), and for all integers n >= 1 is \(\lfloor n/m \rfloor\).
Key Concepts
Number TheoryInteger DivisionFloor Function
Number Theory
Number theory is a branch of mathematics dedicated to studying the properties and relationships of integers. It involves exploring such concepts as divisibility, prime numbers, and modular arithmetic. For our exercise, understanding divisibility is crucial; it allows us to classify numbers based on whether one integer can be divided by another without leaving a remainder.
When we speak of multiples of an integer, we refer to a set of numbers that can be expressed as the product of that integer and some other integer. For example, multiples of 3 include 3, 6, 9, and so on. These are all numbers that can be divided by 3 with zero remainder. Focusing on number theory helps students identify patterns within the set of multiples, which is essential when solving problems that require counting multiples within a given interval.
When we speak of multiples of an integer, we refer to a set of numbers that can be expressed as the product of that integer and some other integer. For example, multiples of 3 include 3, 6, 9, and so on. These are all numbers that can be divided by 3 with zero remainder. Focusing on number theory helps students identify patterns within the set of multiples, which is essential when solving problems that require counting multiples within a given interval.
Integer Division
Integer division is closely tied to the concept of divisibility in number theory. It refers to the process of dividing one integer by another and obtaining a quotient that is also an integer. When dividing two integers, if the divisor does not divide the dividend exactly, the result is typically a fraction or decimal. However, in the context of our exercise, we're only interested in the integer part of that quotient.
For instance, if we take the integer division of 10 by 3, we don't get the exact value which would be approximately 3.333. Instead, we only consider the integer portion, which is 3. This notion of discarding any fractional part is fundamental when calculating the number of multiples of an integer within a range since we only want to count whole multiples and not any partial ones.
For instance, if we take the integer division of 10 by 3, we don't get the exact value which would be approximately 3.333. Instead, we only consider the integer portion, which is 3. This notion of discarding any fractional part is fundamental when calculating the number of multiples of an integer within a range since we only want to count whole multiples and not any partial ones.
Floor Function
The floor function, denoted as \(\lfloor x \rfloor\), is a mathematical function that maps a real number to the largest previous integer. In other words, it 'rounds down' any given number to the nearest whole number that is not greater than the original number. This is supremely relevant when counting multiples of an integer within a closed interval because it allows us to find the largest multiple of the integer within that range.
For example, the floor function applied to 4.9 is 4, because 4 is the largest integer less than or equal to 4.9. In the context of our exercise, the floor function tells us exactly how many times the integer fits into another number without going over. The expression \(\lfloor x/m \rfloor\) thus represents the number of multiples of \(m\) up to \(x\), effectively answering the question posed in the textbook problem.
For example, the floor function applied to 4.9 is 4, because 4 is the largest integer less than or equal to 4.9. In the context of our exercise, the floor function tells us exactly how many times the integer fits into another number without going over. The expression \(\lfloor x/m \rfloor\) thus represents the number of multiples of \(m\) up to \(x\), effectively answering the question posed in the textbook problem.
Other exercises in this chapter
Problem 1
Let \(a, b, d \in \mathbb{Z}\) with \(d \neq 0 .\) Show that \(a \mid b\) if and only if \(d a \mid d b\).
View solution Problem 2
Let \(n\) be a composite integer. Show that there exists a prime \(p\) dividing \(n,\) with \(p \leq n^{1 / 2}\).
View solution Problem 4
Let \(x \in \mathbb{R}\). Show that \(2\lfloor x\rfloor \leq\lfloor 2 x\rfloor \leq 2\lfloor x\rfloor+1\).
View solution Problem 5
Let \(x \in \mathbb{R}\) and \(n \in \mathbb{Z}\) with \(n>0 .\) Show that \(\lfloor\lfloor x\rfloor / n\rfloor=\lfloor x / n\rfloor ;\) in particular, \(\lfloo
View solution