Problem 3
Question
Find the magnitude of the linear momentum of (a) a \(7.1-\mathrm{kg}\) bowling ball traveling at \(12 \mathrm{~m} / \mathrm{s}\) and \((\mathrm{b})\) a \(1200-\mathrm{kg}\) automobile traveling at \(90 \mathrm{~km} / \mathrm{h}\).
Step-by-Step Solution
Verified Answer
Bowling Ball: 85.2 kg·m/s; Automobile: 30000 kg·m/s.
1Step 1: Understanding Linear Momentum
Linear momentum is the product of an object's mass and velocity. It is given by the formula: \( p = mv \), where \( p \) is the linear momentum, \( m \) is the mass, and \( v \) is the velocity.
2Step 1: Convert Units for the Automobile
Before calculating the momentum for the automobile, convert its velocity from kilometers per hour to meters per second. Using the conversion: \(1 \, \text{km/h} = \frac{1}{3.6} \, \text{m/s}\), we get: \[ v = 90 \, \text{km/h} = 90 \times \frac{1}{3.6} \, \text{m/s} \approx 25 \, \text{m/s} \]
3Step 2: Calculate Momentum for the Bowling Ball
Use the momentum formula for the bowling ball: \( m = 7.1 \, \text{kg} \), \( v = 12 \, \text{m/s} \) Calculate: \[ p = mv = 7.1 \, \text{kg} \times 12 \, \text{m/s} = 85.2 \, \text{kg} \cdot \text{m/s} \]
4Step 3: Calculate Momentum for the Automobile
Use the momentum formula for the automobile with the converted velocity: \( m = 1200 \, \text{kg} \), \( v = 25 \, \text{m/s} \) (after conversion) Calculate: \[ p = mv = 1200 \, \text{kg} \times 25 \, \text{m/s} = 30000 \, \text{kg} \cdot \text{m/s} \]
5Step 5: Conclude With Results
The linear momentum of the bowling ball is \(85.2 \, \text{kg} \cdot \text{m/s}\), and the linear momentum of the automobile is \(30000 \, \text{kg} \cdot \text{m/s}\).
Key Concepts
Mass and VelocityUnit ConversionMomentum Calculation
Mass and Velocity
To understand linear momentum, we first need to understand its components: mass and velocity. Mass refers to how much matter an object contains, often measured in kilograms. It determines how much an object resists acceleration when a force is applied. Velocity, on the other hand, refers to the speed of the object in a specific direction, typically measured in meters per second (m/s). Velocity is not just about how fast something moves; it's also about the direction it's moving in. Together, these two factors form the core of linear momentum.
- Mass - A scalar quantity indicating the amount of matter.
- Velocity - A vector quantity indicating speed and direction.
Unit Conversion
Before calculating linear momentum, it's essential to have consistent measurement units. Often, we need to convert units to ensure they align properly for accurate calculations. This is known as unit conversion. For instance, you might have measured velocity in kilometers per hour (km/h) but need to convert this to meters per second (m/s) for consistency with the International System of Units (SI).
The conversion factor from kilometers per hour to meters per second is:
The conversion factor from kilometers per hour to meters per second is:
- To convert, multiply the velocity by \( \frac{1}{3.6} \). So, if you have a velocity of 90 km/h:
\[ v = 90 \times \frac{1}{3.6} \approx 25 \, \text{m/s} \]
Momentum Calculation
With mass and velocity understood and units correctly converted, you're ready to calculate momentum. Linear momentum is calculated using the formula:
\[ p = mv \]Where \(p\) represents momentum, \(m\) is mass, and \(v\) is velocity.
\[ p = mv \]Where \(p\) represents momentum, \(m\) is mass, and \(v\) is velocity.
- For a bowling ball with mass \(7.1 \, \text{kg}\) and velocity \(12 \, \text{m/s}\):
\[ p = 7.1 \, \text{kg} \times 12 \, \text{m/s} = 85.2 \, \text{kg} \cdot \text{m/s} \] - For an automobile weighing \(1200 \, \text{kg}\) moving at \(25 \, \text{m/s}\) (after converting from 90 km/h):
\[ p = 1200 \, \text{kg} \times 25 \, \text{m/s} = 30000 \, \text{kg} \cdot \text{m/s} \]
Other exercises in this chapter
Problem 1
If a \(60-\mathrm{kg}\) woman is riding in a car traveling at \(90 \mathrm{~km} / \mathrm{h}\), what is her linear momentum relative to (a) the ground and (b) t
View solution Problem 2
The linear momentum of a runner in a 100 -m dash is \(7.5 \times 10^{2} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\). If the runner's speed is \(10 \mathrm{~m}
View solution Problem 4
In a football game, a lineman usually has more mass than a running back. (a) Will a lineman always have greater linear momentum than a running back? Why? (b) Wh
View solution Problem 5
A 0.150 -kg baseball traveling with a horizontal speed of \(4.50 \mathrm{~m} / \mathrm{s}\) is hit by a bat and then moves with a speed of \(34.7 \mathrm{~m} /
View solution