Problem 2
Question
The linear momentum of a runner in a 100 -m dash is \(7.5 \times 10^{2} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\). If the runner's speed is \(10 \mathrm{~m} / \mathrm{s}\), what is his mass?
Step-by-Step Solution
Verified Answer
The runner's mass is 75 kg.
1Step 1: Understand the Problem
We are given the linear momentum of a runner and their speed. We need to determine the runner's mass.
2Step 2: Formula Identification
The formula for linear momentum is given by \( p = m imes v \), where \( p \) is momentum, \( m \) is mass, and \( v \) is velocity (speed).
3Step 3: Rearrange the Formula
To find the mass, we rearrange the formula to solve for \( m \): \( m = \frac{p}{v} \).
4Step 4: Substitute the Values
Substitute the given values into the rearranged formula: \( m = \frac{7.5 \times 10^2 \mathrm{~kg} \cdot \mathrm{m/s}}{10 \mathrm{~m/s}} \).
5Step 5: Perform the Calculation
Calculate the mass by dividing the momentum by the speed: \( m = 75 \mathrm{~kg} \).
Key Concepts
Momentum FormulaMass CalculationVelocity in Physics
Momentum Formula
In physics, momentum is a fundamental concept that describes the quantity of motion an object has. It is a vector quantity, which means it has both magnitude and direction:
The higher the momentum, the harder it is to bring the object to rest.
In our exercise, the runner's momentum is given as \( 7.5 \times 10^2 \, \text{kg} \cdot \text{m/s} \).
This tells us how much force, or energy, would be required to stop the runner in motion or change the speed.
- Momentum is denoted by the symbol \( p \).
- The formula for linear momentum is \( p = m \times v \).
- Here, \( m \) stands for mass and \( v \) is velocity.
The higher the momentum, the harder it is to bring the object to rest.
In our exercise, the runner's momentum is given as \( 7.5 \times 10^2 \, \text{kg} \cdot \text{m/s} \).
This tells us how much force, or energy, would be required to stop the runner in motion or change the speed.
Mass Calculation
Calculating mass from momentum requires rearranging the momentum formula. Once you have the formula, \( p = m \times v \), you can solve for mass:
The linear momentum value is \( 7.5 \times 10^2 \, \text{kg} \cdot \text{m/s} \) and the velocity is \( 10 \, \text{m/s} \).
Substituting, \( m = \frac{7.5 \times 10^2}{10} = 75 \, \text{kg} \).
This calculation confirms that the mass of the runner is 75 kg.
Understanding this step is crucial as it teaches how physical properties are interconnected through mathematical expressions.
- Rearrange the formula to \( m = \frac{p}{v} \).
- This rearrangement helps us express mass in terms of momentum and velocity.
The linear momentum value is \( 7.5 \times 10^2 \, \text{kg} \cdot \text{m/s} \) and the velocity is \( 10 \, \text{m/s} \).
Substituting, \( m = \frac{7.5 \times 10^2}{10} = 75 \, \text{kg} \).
This calculation confirms that the mass of the runner is 75 kg.
Understanding this step is crucial as it teaches how physical properties are interconnected through mathematical expressions.
Velocity in Physics
Velocity is a critical physics concept frequently used in motion-related calculations. It informs us about the speed and direction of an object's movement:
This tells us not only how fast the runner is moving but also gives context to the motion, which is a key factor when calculating momentum.
Velocity helps differentiate motion concepts from static elements, highlighting its importance in force calculations, kinetic energy, and more.
- Velocity is denoted by the symbol \( v \).
- It is different from speed as it includes direction.
- Measured in \( \text{meters per second (m/s)} \).
This tells us not only how fast the runner is moving but also gives context to the motion, which is a key factor when calculating momentum.
Velocity helps differentiate motion concepts from static elements, highlighting its importance in force calculations, kinetic energy, and more.
Other exercises in this chapter
Problem 1
If a \(60-\mathrm{kg}\) woman is riding in a car traveling at \(90 \mathrm{~km} / \mathrm{h}\), what is her linear momentum relative to (a) the ground and (b) t
View solution Problem 3
Find the magnitude of the linear momentum of (a) a \(7.1-\mathrm{kg}\) bowling ball traveling at \(12 \mathrm{~m} / \mathrm{s}\) and \((\mathrm{b})\) a \(1200-\
View solution Problem 4
In a football game, a lineman usually has more mass than a running back. (a) Will a lineman always have greater linear momentum than a running back? Why? (b) Wh
View solution Problem 5
A 0.150 -kg baseball traveling with a horizontal speed of \(4.50 \mathrm{~m} / \mathrm{s}\) is hit by a bat and then moves with a speed of \(34.7 \mathrm{~m} /
View solution