Problem 3
Question
Fill in the blanks. a. \(F^{3}+L^{3}=(\quad+\quad)\left(F^{2}-F L+L^{2}\right)\) b. \(F^{3}-L^{3}=(F \quad L)(\quad+F L+\quad)\)
Step-by-Step Solution
Verified Answer
a. \( F + L \) b. \( F - L, \ F^2 + FL + L^2 \)
1Step 1: Identify Formula Structure
The expressions given in the question resemble the formulas for the sum and difference of cubes. For sum of cubes: \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\). For difference of cubes: \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\). Let's use these formulas in the given expressions.
2Step 2: Solve Part (a)
Given expression: \(F^3 + L^3 = ( ext{blank} + ext{blank})(F^2 - FL + L^2)\). By comparing this to the formula for sums of cubes: \( a^3 + b^3 = (a + b)(a^2 - ab + b^2) \), it is clear that the blanks represent \(F + L\). Therefore, \(F^3 + L^3 = (F + L)(F^2 - FL + L^2)\).
3Step 3: Solve Part (b)
Given expression: \(F^3 - L^3 = (F ext{ blank } L)( ext{blank} + FL + ext{blank})\). This matches the difference of cubes formula: \( a^3 - b^3 = (a - b)(a^2 + ab + b^2) \). Thus, the blanks represent \(F\), \(L\), and \(L^2\) respectively. So, \(F^3 - L^3 = (F - L)(F^2 + FL + L^2)\).
Key Concepts
Sum of CubesDifference of CubesFactoring
Sum of Cubes
The sum of cubes is a formula used to factor expressions of the form \( a^3 + b^3 \). This might look a bit intimidating at first, but the formula makes it easier:\[a^3 + b^3 = (a + b)(a^2 - ab + b^2)\]Why is this helpful? When faced with an expression like \( F^3 + L^3 \), using the formula allows us to break it down. The first term \( (a + b) \) simply adds the cube roots of the terms, and the second term \( (a^2 - ab + b^2) \) puts together their squares and the product with a minus. This formula provides a neat factorization of the sum of two cubes—transforming it into a straight multiplication that joins polynomials together.
Difference of Cubes
The difference of cubes is another handy formula for factoring expressions that look like \( a^3 - b^3 \). Again, the formula is here to save the day:\[a^3 - b^3 = (a - b)(a^2 + ab + b^2)\]If we break it down:
- The first factor \( (a - b) \) is just subtracting one cube root from the other.
- The second factor \( (a^2 + ab + b^2) \) organizes the squares of the terms and the product with a plus this time.
Factoring
Factoring is a cornerstone concept in algebra, a process that splits an expression into products of simpler ones. In our exercises, factoring focuses on special polynomial identities—the sum and difference of cubes.
To factor efficiently, apply:
- The sum of cubes formula whenever you see the sum of two cubes.
- The difference of cubes formula for the difference of two cubes.
Other exercises in this chapter
Problem 3
Fill in the blanks. Consider \(25 x^{2}+30 x+9\). a. The first term is the square of________. b. The last term is the square of ________. c. The middle term is
View solution Problem 3
Fill in the blanks. The _____ coefficient of \(x^{2}-3 x+2\) is 1
View solution Problem 3
The first terms of the binomial factors \((5 y+1)(y+3)\) are _____ and _____. The second terms of the binomial factors are _____ and _____.
View solution Problem 3
Fill in the blanks. To factor \(m^{3}+3 m^{2}+4 m+12\) by __________ we begin by writing \(m^{2}(m+3)+4(m+3)\)
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