Problem 29
Question
Use interval notation to express solution sets and graph each solution set on a number line. Solve each linear inequality. $$3 x-7 \geq 13$$
Step-by-Step Solution
Verified Answer
The solution to the inequality \(3x - 7 \geq 13\) is \(x \geq \frac{20}{3}\). In interval notation, this solution is written as \([\frac{20}{3}, \infty)\). On the number line, the solution set includes the point \(\frac{20}{3}\) and stretches towards infinity to the right from this point.
1Step 1: Solving the Inequality
Start by isolating the variable \(x\). This can be done by performing the same mathematical operations on both sides of the inequality until \(x\) is by itself on one side. \n In this case, add 7 to both sides of the inequality to get rid of the -7 on the left side. The inequality now looks like this: \(3x \geq 20\). Then, divide both sides by 3 to solve for \(x\). We get \(x \geq \frac{20}{3}\).
2Step 2: Applying Interval Notation
Interval notation is a simplified form of writing the solution to an inequality. In this case, \(x \geq \frac{20}{3}\) means that \(x\) can be any number that is greater than or equal to \(\frac{20}{3}\). In interval notation, this is written as \([\frac{20}{3}, \infty)\). The square bracket indicates that \(\frac{20}{3}\) is included in the solution set, and the parenthesis implies that infinity is not a reachable number but the values of \(x\) tend to infinity.
3Step 3: Graphing the Solution Set
To graph this solution set on a number line, one starts by drawing a line. The point corresponding to \(\frac{20}{3}\) needs to be marked with a solid dot (which signifies that the number is included in the solution set) and an arrow pointing towards the right (to signify that all numbers greater than this point are part of the solution set).
Other exercises in this chapter
Problem 29
In Exercises \(29-44\), perform the indicated operations and write the result in standard form. $$ \sqrt{-64}-\sqrt{-25} $$
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Solve each equation in Exercises \(15-34\) by the square root property. $$ (3 x+2)^{2}=9 $$
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Check all proposed solutions. $$ \sqrt{3 \sqrt{x+1}}=\sqrt{3 x-5} $$
View solution Problem 29
Contain linear equations with constants in denominators. Solve equation. \(\frac{x+1}{3}=5-\frac{x+2}{7}\)
View solution