Problem 29
Question
The terminal point \(P(x, y)\) determined by a real number \(t\) is given. Find \(\sin t, \cos t,\) and \(\tan t\). $$\left(\frac{3}{5}, \frac{4}{5}\right)$$
Step-by-Step Solution
Verified Answer
\(\sin t = \frac{4}{5}, \cos t = \frac{3}{5}, \tan t = \frac{4}{3}\).
1Step 1: Identify the Terminal Point Coordinates
The terminal point given is \(P(x, y) = \left(\frac{3}{5}, \frac{4}{5}\right)\). From this, we identify \(x = \frac{3}{5}\) and \(y = \frac{4}{5}\).
2Step 2: Determine \(\sin t\)
The sine of the angle \(t\) is the ratio of the \(y\)-coordinate to the hypotenuse of the unit circle. Since we assume this point is on the unit circle, the hypotenuse is 1. Thus, \(\sin t = y = \frac{4}{5}\).
3Step 3: Determine \(\cos t\)
The cosine of the angle \(t\) is the ratio of the \(x\)-coordinate to the hypotenuse of the unit circle. Hence, \(\cos t = x = \frac{3}{5}\).
4Step 4: Determine \(\tan t\)
The tangent of the angle \(t\) is the ratio of the \(y\)-coordinate to the \(x\)-coordinate. Therefore, \(\tan t = \frac{y}{x} = \frac{\frac{4}{5}}{\frac{3}{5}} = \frac{4}{3}\).
Key Concepts
Understanding the Sine FunctionExploring the Cosine FunctionDiving into the Tangent Function
Understanding the Sine Function
The sine function is a critical concept in trigonometry that relates to the unit circle, which has a radius of one.
In the context of a point \(P(x, y)\) on the unit circle, \( \sin t \) is defined as the \(y\)-coordinate of that point.
In other words, if you have a point \(P(x, y) = \left(\frac{3}{5}, \frac{4}{5}\right)\), the sine of the angle \(t\) would simply be the \(y\)-value, which is \(\frac{4}{5}\).
In the context of a point \(P(x, y)\) on the unit circle, \( \sin t \) is defined as the \(y\)-coordinate of that point.
In other words, if you have a point \(P(x, y) = \left(\frac{3}{5}, \frac{4}{5}\right)\), the sine of the angle \(t\) would simply be the \(y\)-value, which is \(\frac{4}{5}\).
- The sine function indicates the vertical distance of the point \(P(x,y)\) from the origin.
- It ranges between -1 and 1 as it represents coordinates on the unit circle.
Exploring the Cosine Function
Similarly to the sine function, the cosine function is also fundamentally linked to the unit circle.
The cosine of an angle \( t \) is the \(x \)-coordinate of the point on the unit circle determined by that angle.
In our example of the terminal point \(P(x, y) = \left(\frac{3}{5}, \frac{4}{5}\right)\), the \(x\)-value, or cosine, is \(\frac{3}{5}\).
The cosine of an angle \( t \) is the \(x \)-coordinate of the point on the unit circle determined by that angle.
In our example of the terminal point \(P(x, y) = \left(\frac{3}{5}, \frac{4}{5}\right)\), the \(x\)-value, or cosine, is \(\frac{3}{5}\).
- Cosine represents how far along the horizontal axis the point \(P(x,y)\) is from the origin.
- Just like the sine function, cosine values are bounded between -1 and 1.
Diving into the Tangent Function
The tangent function is a bit different from sine and cosine as it represents a ratio rather than just a coordinate.
The tangent of an angle \( t \) is calculated by dividing the \(y \)-coordinate by the \(x \)-coordinate at the terminal point on the unit circle.
For our terminal point \(P(x, y) = \left(\frac{3}{5}, \frac{4}{5}\right)\), the tangent is \(\tan t = \frac{4}{3}\).
The tangent of an angle \( t \) is calculated by dividing the \(y \)-coordinate by the \(x \)-coordinate at the terminal point on the unit circle.
For our terminal point \(P(x, y) = \left(\frac{3}{5}, \frac{4}{5}\right)\), the tangent is \(\tan t = \frac{4}{3}\).
- The tangent function informs us of the steepness or inclination of the line connecting the origin to \(P(x,y)\).
- While it doesn't have a fixed range as sine and cosine, it is undefined when \( x = 0 \) since you cannot divide by zero.
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