Problem 29
Question
Blood Pressure Each time your heart beats, your blood pressure increases, then decreases as the heart rests between beats. A certain person's blood pressure is modeled by the function $$ p(t)=115+25 \sin (160 \pi t) $$ where \(p(t)\) is the pressure in \(\mathrm{mmHg}\) at time \(t,\) measured in minutes. (a) Find the amplitude, period, and frequency of \(p\) (b) Sketch a graph of \(p\) (c) If a person is exercising, his or her heart beats faster. How does this affect the period and frequency of \(p ?\)
Step-by-Step Solution
Verified Answer
(a) Amplitude=25, Period=1/80 min, Frequency=80 cycles/min. (c) Exercise increases frequency, decreases period.
1Step 1: Identify the Amplitude
The amplitude of a sinusoidal function of the form \( p(t) = A + B \sin(Ct) \) is given by the absolute value of the coefficient of the sine function. Here, the amplitude is \( |25| = 25 \).
2Step 2: Determine the Period
The period of a sine function \( \sin(Ct) \) is given by \( \frac{2\pi}{C} \). Therefore, for \( p(t) = 115 + 25 \sin(160\pi t) \), \( C = 160\pi \). So, the period is \( \frac{2\pi}{160\pi} = \frac{1}{80} \) minutes.
3Step 3: Calculate the Frequency
The frequency is the reciprocal of the period. So, the frequency is \( \frac{1}{\text{Period}} = 80 \) cycles per minute.
4Step 4: Sketch the Graph
To sketch the function \( p(t) = 115 + 25 \sin(160\pi t) \), note that the graph oscillates between \( 115 - 25 = 90 \) and \( 115 + 25 = 140 \) with a period of \( \frac{1}{80} \) minutes. Plot these key characteristics and draw the sinusoidal wave.
5Step 5: Effect of Exercise on Period and Frequency
If a person exercises, the heart beats faster. This results in a higher frequency of the blood pressure cycle, which means the period will decrease. The general behavior indicates a more frequent oscillation during exercise.
Key Concepts
AmplitudePeriodFrequency
Amplitude
The amplitude of a trigonometric function, like sine and cosine, refers to the distance from the middle of the wave to its peak, or its trough. In simpler terms, we can think of amplitude as the height of the wave. In the function given in the exercise, \( p(t) = 115 + 25 \sin(160\pi t) \), the amplitude is represented by the coefficient of the sine term, which is 25.
- The sine term oscillates between -1 and 1.
- Therefore, multiplying it by 25 means the oscillation will be between -25 and 25.
- This oscillation is added to the base value of 115 mmHg, resulting in a pressure fluctuation between 90 mmHg and 140 mmHg.
Period
The period of a trigonometric function is the duration it takes for the function to complete a full cycle. In the context of the blood pressure function \( p(t) = 115 + 25 \sin(160\pi t) \), the period can be found using the formula for the period of a sine function, \( \frac{2\pi}{C} \), where \( C \) is the coefficient of \( t \) in the sin function.
Calculating the Period
To calculate the period of \( p(t) \):- Identify \( C = 160\pi \).
- The period is \( \frac{2\pi}{160\pi} = \frac{1}{80} \) minutes.
Frequency
In trigonometric functions, frequency is the number of complete cycles a function goes through in a unit of time. It is essentially the inverse of the period and indicates how often the waves repeat. When it comes to the function \( p(t) = 115 + 25 \sin(160\pi t) \), understanding frequency tells us about the speed of oscillations per minute.
Understanding Frequency
- The frequency is calculated as the reciprocal of the period.
- Given a period \( \frac{1}{80} \) minutes, the frequency becomes \( 80 \) cycles per minute.
Other exercises in this chapter
Problem 29
The terminal point \(P(x, y)\) determined by a real number \(t\) is given. Find \(\sin t, \cos t,\) and \(\tan t\). $$\left(\frac{3}{5}, \frac{4}{5}\right)$$
View solution Problem 29
Find the terminal point \(P(x, y)\) on the unit circle determined by the given value of \(t .\) $$t=\frac{2 \pi}{3}$$
View solution Problem 29
Find the amplitude, period, and phase shift of the function, and graph one complete period. $$y=\cos \left(x-\frac{\pi}{2}\right)$$
View solution Problem 30
Find the exact value of the expression, if it is defined. $$\tan ^{-1}\left(\tan \left(\frac{\pi}{4}\right)\right)$$
View solution