Problem 29
Question
In Problems , determine the points of intersection of the given line and the three coordinate planes. $$ x=4-2 t, y=1+2 t, z=9+3 t $$
Step-by-Step Solution
Verified Answer
The points of intersection are (10, -5, 0), (5, 0, \frac{15}{2}), and (0, 5, 15).
1Step 1: Define the Intersection with the XY-plane
For the line to intersect the XY-plane, the z-coordinate must be 0. Use the expression for z: \( z = 9 + 3t = 0 \). Solve this equation to find the value of t that results in this intersection.
2Step 2: Solve for t in XY-plane Intersection
Set up the equation: \[ 9 + 3t = 0 \]Solving for t gives:\[ 3t = -9 \]\[ t = -3 \]
3Step 3: Calculate Intersection Coordinates in XY-plane
Substitute \( t = -3 \) back into the equations for x and y: x: \( x = 4 - 2(-3) = 4 + 6 = 10 \) y: \( y = 1 + 2(-3) = 1 - 6 = -5 \)Thus, the point of intersection with the XY-plane is \( (10, -5, 0) \).
4Step 4: Define the Intersection with the XZ-plane
For the line to intersect the XZ-plane, the y-coordinate must be 0. Use the expression for y: \( y = 1 + 2t = 0 \). Solve this equation to find the value of t.
5Step 5: Solve for t in XZ-plane Intersection
Set up the equation: \[ 1 + 2t = 0 \]Solving for t gives:\[ 2t = -1 \]\[ t = -\frac{1}{2} \]
6Step 6: Calculate Intersection Coordinates in XZ-plane
Substitute \( t = -\frac{1}{2} \) back into the equations for x and z: x: \( x = 4 - 2\left(-\frac{1}{2}\right) = 4 + 1 = 5 \) z: \( z = 9 + 3\left(-\frac{1}{2}\right) = 9 - \frac{3}{2} = \frac{15}{2} \)Thus, the point of intersection with the XZ-plane is \( (5, 0, \frac{15}{2}) \).
7Step 7: Define the Intersection with the YZ-plane
For the line to intersect the YZ-plane, the x-coordinate must be 0. Use the expression for x: \( x = 4 - 2t = 0 \). Solve this equation to find the value of t.
8Step 8: Solve for t in YZ-plane Intersection
Set up the equation: \[ 4 - 2t = 0 \]Solving for t gives:\[ 2t = 4 \]\[ t = 2 \]
9Step 9: Calculate Intersection Coordinates in YZ-plane
Substitute \( t = 2 \) back into the equations for y and z: y: \( y = 1 + 2(2) = 1 + 4 = 5 \) z: \( z = 9 + 3(2) = 9 + 6 = 15 \)Thus, the point of intersection with the YZ-plane is \( (0, 5, 15) \).
Key Concepts
Points of IntersectionParametric EquationsCoordinate Planes
Points of Intersection
In coordinate geometry, points of intersection are crucial for understanding how objects intersect within the coordinate space. When a line intersects a plane, the intersection is often a single point.
This concept is very important when working on problems involving coordinate planes like XY-plane, XZ-plane, or YZ-plane.
Understanding Intersection on Planes:
This concept is very important when working on problems involving coordinate planes like XY-plane, XZ-plane, or YZ-plane.
Understanding Intersection on Planes:
- XY-plane: In the XY-plane, the z-coordinate is zero. This means we set the z equation of the line to zero to find the point of intersection.
- Xz-plane: Here, the y-coordinate must be zero, leading to setting the y equation of the line to zero.
- YZ-plane: Similarly, the x-coordinate must be zero, requiring us to use the x equation equivalent to zero.
Parametric Equations
Parametric equations represent lines in a three-dimensional space using parameters, typically denoted as \( t \). These equations express the coordinates \( x \), \( y \), and \( z \) each as functions of \( t \).
For example, the given line is defined by:
It's an efficient way to handle complex spatial relationships in geometry.
For example, the given line is defined by:
- \( x = 4 - 2t \)
- \( y = 1 + 2t \)
- \( z = 9 + 3t \)
It's an efficient way to handle complex spatial relationships in geometry.
Coordinate Planes
Coordinate planes form the foundational elements in three-dimensional geometry. There are three primary coordinate planes:
Knowing how lines intersect these planes will help in mastering three-dimensional geometry concepts.
- XY-plane: It includes all points where the z-coordinate is zero. Think of it as a flat sheet extending indefinitely within the X and Y axis dimensions.
- XZ-plane: This plane includes all points where the y-coordinate is zero, extending across the X and Z axis dimensions.
- YZ-plane: Consists of all points where the x-coordinate is zero, covering the Y and Z axis dimensions.
Knowing how lines intersect these planes will help in mastering three-dimensional geometry concepts.
Other exercises in this chapter
Problem 28
Find a unit vector (a) in the same direction as \(\mathbf{a}\), and (b) in the opposite direction of \(\mathbf{a}\). \(\mathbf{a}=\langle 1,-\sqrt{3}\rangle\)
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Explain why \(f(x)=\frac{x}{x^{2}+4 x+3}\) is a vector in \(C[0,3]\) but not a vector in \(C[-3,0]\).
View solution Problem 29
Use the distance formula to prove that the given points are collinear. $$ P_{1}(1,2,0), P_{2}(-2,-2,-3), P_{3}(7,10,6) $$
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\( \mathbf{a}=\langle 2,8\rangle\) and \(\mathbf{b}=\langle 3,4\rangle .\) Find a unit vector in the same direction as the given vector. \(\mathbf{a}+\mathbf{b}
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