Problem 29
Question
In Exercises 23-32, find the \( x \)- and \( y \)-intercepts of the graph of the equation. \( y = 2x^3-4x^2 \)
Step-by-Step Solution
Verified Answer
The \( x \)-intercepts are \( x_1 = 0 \) and \( x_2 = 2 \) while the \( y \)-intercept is (0,0).
1Step 1: Finding the \( x \)-intercepts
To find the \( x \)-intercepts we need to set \( y = 0 \) and solve for \( x \). So: \[0 = 2x^3-4x^2\]First, we factor out the common factor \( x^2 \):\[0 = x^2 (2x - 4)\]Next we set each factor to zero:\[x^2 = 0 \text{ and } 2x-4 = 0\]Solving these we get \( x_1 = 0, x_2 = 2 \) which are our \( x \)-intercepts.
2Step 2: Finding the \( y \)-intercepts
To find the \( y \)-intercepts we need to set \( x = 0 \) and solve for \( y \). So: \[y = 2 * 0^3 - 4 * 0^2 = 0\]So, the \( y \)-intercept is (0,0).
Key Concepts
Finding x-interceptsFactoring PolynomialsSolving Cubic Equations
Finding x-intercepts
When delving into the world of algebraic functions, understanding how to locate the points where the graph of the function crosses the x-axis, known as the x-intercepts, is crucial. Imagine you're on a treasure hunt, and the x-intercept marks the spot on the map. To uncover this treasure, we search for when the output value, represented by the variable y, equals zero. An easy way to visualize this is by picturing a rollercoaster that briefly touches ground level—that point where it kisses the ground, is the intercept in question.
For quadratic equations and higher, such as the given cubic function, this often involves factoring. The process is similar to pulling out toys from a treasure chest; if possible, we look for common factors and pull them out of the equation. In our exercise, we plucked out an x2, simplifying our task to finding the zeros of what remains. We're essentially solving a simpler puzzle within the larger riddle. Like splitting a lock's combination into smaller parts, we deal with each factor separately to find the x-intercepts, which are, in this case, x = 0 and x = 2.
For quadratic equations and higher, such as the given cubic function, this often involves factoring. The process is similar to pulling out toys from a treasure chest; if possible, we look for common factors and pull them out of the equation. In our exercise, we plucked out an x2, simplifying our task to finding the zeros of what remains. We're essentially solving a simpler puzzle within the larger riddle. Like splitting a lock's combination into smaller parts, we deal with each factor separately to find the x-intercepts, which are, in this case, x = 0 and x = 2.
Factoring Polynomials
The art of factoring polynomials is akin to dismantling a complex piece of machinery into its component parts. It's about breaking down expressions into the simplest building blocks—these are the 'factors' that, when multiplied together, give back the original polynomial. Think of it as reverse-engineering, where we're looking for the original blueprints of the algebraic structure.
For our exercise, the polynomial in question is cubic, giving it a bit more complexity. We first identify any common factors among the terms, just like looking for repeating patterns or pieces that clearly fit together. In the given function y = 2x3 - 4x2, we can see that both terms share an x2. Extracting this common piece streamlines the equation, leaving us with a clearer path to solve the puzzle. Factoring not only simplifies the equation but also paves the way to finding both x-intercepts and y-intercepts.
For our exercise, the polynomial in question is cubic, giving it a bit more complexity. We first identify any common factors among the terms, just like looking for repeating patterns or pieces that clearly fit together. In the given function y = 2x3 - 4x2, we can see that both terms share an x2. Extracting this common piece streamlines the equation, leaving us with a clearer path to solve the puzzle. Factoring not only simplifies the equation but also paves the way to finding both x-intercepts and y-intercepts.
Solving Cubic Equations
Once we enter the realm of solving cubic equations, we're stepping up the game—it's like moving from checkers to three-dimensional chess. Unlike the easier to manage linear or quadratic equations, cubic equations can behave in unexpected ways, often leading to multiple turning points and possibly more than one x-intercept. To solve such a conundrum, one effective strategy is to use factoring, a method we've touched upon earlier, which can simplify our quest significantly.
Our goal here is to express the cubic equation 2x3 - 4x2 = 0 as a product of factors that can each be set to zero. By pulling out the greatest common factor—x2 in this case, and then examining the quadratic factor (2x-4) that remains, we create a clearer path to identify potential solutions. These solutions paint a picture of where the function's graph touches or crosses the x-axis and are the keys to solving the holistic cubic puzzle.
Our goal here is to express the cubic equation 2x3 - 4x2 = 0 as a product of factors that can each be set to zero. By pulling out the greatest common factor—x2 in this case, and then examining the quadratic factor (2x-4) that remains, we create a clearer path to identify potential solutions. These solutions paint a picture of where the function's graph touches or crosses the x-axis and are the keys to solving the holistic cubic puzzle.
Other exercises in this chapter
Problem 29
In Exercises 19-36, determine whether the equation represents \(y\) as a function of \(x\). \(y = \sqrt{16-x^2}\)
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In Exercises 29-40, plot the points and find the slope of the line passing through the pair of points. \( (0, 9) \), \( (6, 0) \)
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In Exercises 27-38, find the distance between the points. \( (-3, -1) \), \( (2, -1) \)
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In Exercises 27-30, use the given value of \(k\) to complete the table for the inverse variation model \(y = \frac{k}{x^2}\) Plot the points on a rectangular co
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