Problem 29
Question
For the following exercises, factor the polynomial. $$ 144 b^{2}-25 c^{2} $$
Step-by-Step Solution
Verified Answer
The polynomial \(144b^2 - 25c^2\) factors as \((12b - 5c)(12b + 5c)\).
1Step 1: Identifying the Type of Polynomial
The polynomial given is \(144b^2 - 25c^2\), which is a difference of squares because both \(144b^2\) and \(25c^2\) are perfect squares.
2Step 2: Express Each Term as a Square
We can express \(144b^2\) as \((12b)^2\) and \(25c^2\) as \((5c)^2\). This confirms that the polynomial is a difference of squares.
3Step 3: Apply the Difference of Squares Formula
Use the difference of squares formula, \(a^2 - b^2 = (a - b)(a + b)\), where \(a=12b\) and \(b=5c\).
4Step 4: Factor the Polynomial
Substitute \(a=12b\) and \(b=5c\) into the formula to get \((12b - 5c)(12b + 5c)\).
Key Concepts
Difference of SquaresPerfect SquaresPolynomial Expressions
Difference of Squares
The difference of squares is a special pattern in algebra where you have two perfect squares separated by a subtraction sign. This pattern can be represented as \(a^2 - b^2\). The key to factoring a difference of squares is recognizing this pattern and remembering its corresponding formula:
In the exercise, \(144b^2 - 25c^2\) is a clear example of this pattern. You first identify the two perfect squares: \((12b)^2\) and \((5c)^2\). Once recognized, you apply the difference of squares formula, making factoring straightforward. This method is very efficient, especially when dealing with polynomials in many math problems.
- The formula: \(a^2 - b^2 = (a - b)(a + b)\)
In the exercise, \(144b^2 - 25c^2\) is a clear example of this pattern. You first identify the two perfect squares: \((12b)^2\) and \((5c)^2\). Once recognized, you apply the difference of squares formula, making factoring straightforward. This method is very efficient, especially when dealing with polynomials in many math problems.
Perfect Squares
Perfect squares are expressions that can be written as the square of a monomial. You're likely familiar with numbers like 1, 4, 9, and 16, which are perfect squares because they equal another integer multiplied by itself. Similarly, any expression like \((3x)^2\) or \((2y)^2\) is a perfect square because they represent a term multiplied by itself.
- Important to recognize: the square of a number or an algebraic expression
- Examples: \(x^2\), \((3y)^2\), \(4b^2\)
Polynomial Expressions
Polynomial expressions consist of variables and coefficients, involving terms with different degrees, typically separated by addition or subtraction. They form the foundation for operations in algebra, and come into play often in factoring.
Take the given exercise: \(144b^2 - 25c^2\). Its form — with two terms, both being perfect squares — immediately suggests certain strategies, like the difference of squares. In polynomial expressions, identifying the type of expression is often the crucial first step towards finding a viable solution method.
- Polynomial terms: like \(3x^2\), \(-4x\), or \(2\)
- Polynomials can be simple, like \(x - 2\), or more complex, like \(5x^2 + 3x + 1\)
Take the given exercise: \(144b^2 - 25c^2\). Its form — with two terms, both being perfect squares — immediately suggests certain strategies, like the difference of squares. In polynomial expressions, identifying the type of expression is often the crucial first step towards finding a viable solution method.
Other exercises in this chapter
Problem 28
For the following exercises, solve for the variable. $$ 8(x+3)=64 $$
View solution Problem 28
Solve for the variable. $$ 8(x+3)=64 $$
View solution Problem 29
For the following exercises, divide the rational expressions. $$ \frac{144 b^{2}-25}{72 b^{2}-6 b-10} \div \frac{18 b^{2}-21 b+5}{36 b^{2}-18 b-10} $$
View solution Problem 29
For the following exercises, simplify each expression. $$ \frac{8}{1-\sqrt{17}} $$
View solution