Problem 28
Question
Solve for the variable. $$ 8(x+3)=64 $$
Step-by-Step Solution
Verified Answer
x = 5
1Step 1: Distribute the 8
First, we will apply the distributive property to the equation. This means multiplying the 8 by each term inside the parentheses. So, multiply 8 by both x and 3: \[ 8 \times x + 8 \times 3 = 8(x + 3) \]This simplifies to:\[ 8x + 24 = 64 \]
2Step 2: Isolate the 8x
Next, we need to get all terms involving x on one side of the equation. We will do this by subtracting 24 from both sides of the equation to isolate the term with x:\[ 8x + 24 - 24 = 64 - 24 \]This simplifies to:\[ 8x = 40 \]
3Step 3: Solve for x
Now that we have 8x isolated, we want to solve for x. To do that, divide both sides of the equation by 8:\[ \frac{8x}{8} = \frac{40}{8} \]This simplifies to:\[ x = 5 \]
Key Concepts
Distributive PropertyEquation SolvingVariable Isolation
Distributive Property
The distributive property is a fundamental concept in algebra that helps simplify expressions and equations. It allows you to multiply a single term across terms inside parentheses.
In the equation given, \[8(x+3)=64\], we employ the distributive property in the first step to eliminate the parentheses. By multiplying 8 by each term inside \((x + 3)\), the expression becomes:
In the equation given, \[8(x+3)=64\], we employ the distributive property in the first step to eliminate the parentheses. By multiplying 8 by each term inside \((x + 3)\), the expression becomes:
- \(8 \times x = 8x\)
- \(8 \times 3 = 24\)
Equation Solving
Equation solving in algebra involves finding the value of the variable that makes the equation true. It requires simplifying the equation step by step to isolate the variable.
From the equation \(8x + 24 = 64\), the goal is to transform it into a simpler form where the variable is on one side.
By identifying like terms and performing basic arithmetic operations, we move towards a solution.
From the equation \(8x + 24 = 64\), the goal is to transform it into a simpler form where the variable is on one side.
By identifying like terms and performing basic arithmetic operations, we move towards a solution.
- First, subtract 24 from both sides of the equation to maintain equality: \[8x + 24 - 24 = 64 - 24\]
- This simplifies to: \[8x = 40\]
Variable Isolation
Variable isolation is the final goal in solving algebraic equations. It involves leaving the variable on one side and having a number or simplified expression on the other.
After distributing and simplifying, the equation \(8x = 40\) is ready for variable isolation.
To isolate \(x\), we divide both sides by 8, which is the coefficient of \(x\):
Remember, the aim is to express \(x\) purely in terms of numbers, and doing so confirms that \(x = 5\) satisfies the original equation. Properly isolating variables is crucial as it reflects the solution to the problem in its simplest form.
After distributing and simplifying, the equation \(8x = 40\) is ready for variable isolation.
To isolate \(x\), we divide both sides by 8, which is the coefficient of \(x\):
- \[\frac{8x}{8} = \frac{40}{8}\]
Remember, the aim is to express \(x\) purely in terms of numbers, and doing so confirms that \(x = 5\) satisfies the original equation. Properly isolating variables is crucial as it reflects the solution to the problem in its simplest form.
Other exercises in this chapter
Problem 28
For the following exercises, simplify the given expression. Write answers with positive exponents. $$ \left(\frac{x^{-3}}{y^{2}}\right)^{-5} $$
View solution Problem 28
For the following exercises, solve for the variable. $$ 8(x+3)=64 $$
View solution Problem 29
For the following exercises, factor the polynomial. $$ 144 b^{2}-25 c^{2} $$
View solution Problem 29
For the following exercises, divide the rational expressions. $$ \frac{144 b^{2}-25}{72 b^{2}-6 b-10} \div \frac{18 b^{2}-21 b+5}{36 b^{2}-18 b-10} $$
View solution