Problem 29
Question
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Focus: \(F(0,2)\)
Step-by-Step Solution
Verified Answer
The equation of the parabola is \(x^2 = 8y\).
1Step 1: Understand the Given Information
We have a parabola with a vertex at the origin, \((0,0)\). We are also given the focus of the parabola, which is \(F(0, 2)\). The typical form of a parabola with a vertical axis is \(x^2 = 4py\), with \(p\) being the distance from the vertex to the focus.
2Step 2: Identify the Parameter p
Since the focus is \((0, 2)\) and the vertex is at the origin \((0,0)\), the distance \(p\) from the vertex to the focus is 2. Thus, \(p = 2\).
3Step 3: Write the Equation of the Parabola
The general formula for a parabola with a vertical axis centered at the origin is \(x^2 = 4py\). By substituting \(p = 2\) into this formula, we get \(x^2 = 4 \times 2 \times y\), which simplifies to \(x^2 = 8y\).
Key Concepts
Vertex of a ParabolaFocus of a ParabolaDistance from Vertex to Focus
Vertex of a Parabola
The vertex of a parabola is a crucial point, as it represents the point where the parabola changes direction. When a parabola opens upwards or downwards, the vertex will be the lowest or highest point, respectively. In this kind of parabola, the vertex is typically represented as the point
- the equation can be simplified to
- turns the parabola either upwards or downwards
Focus of a Parabola
The focus of a parabola is a fixed point that, combined with a directrix, helps define the curve. It lies along the axis of symmetry of the parabola. When a parabola is plotted on a coordinate plane, any point
- is approximately equidistant from the focus
- and the directrix, a line that does not intersect the parabola itself.
Distance from Vertex to Focus
The distance from the vertex to the focus of a parabola, often denoted as
"", determines several aspects about the parabola including its "width" or "narrowness." The greater the distance
- the broader the parabola
- is said to open with a larger spread.
Other exercises in this chapter
Problem 29
Use a graphing device to graph the ellipse. $$\frac{x^{2}}{25}+\frac{y^{2}}{20}=1$$
View solution Problem 29
Complete the square to determine whether the equation represents an ellipse, a parabola, a hyperbola, or a degenerate conic. If the graph is an ellipse, find th
View solution Problem 30
Use a graphing device to graph the hyperbola. $$\frac{x^{2}}{100}-\frac{y^{2}}{64}=1$$
View solution Problem 30
(a) Find the eccentricity and identify the conic. (b) Sketch the conic and label the vertices. $$r=\frac{8}{3+3 \cos \theta}$$
View solution