Problem 28
Question
The perimeter of a triangle is 75 meters. If each of two legs is exactly twice the length of the shortest leg, how long is the shortest leg?
Step-by-Step Solution
Verified Answer
The shortest leg is 15 meters long.
1Step 1: Understand the Problem
We are given a triangle with a perimeter of 75 meters. Two sides are each twice the length of the shortest leg. We need to find the length of the shortest leg.
2Step 2: Assign Variables
Let the length of the shortest leg be denoted as \( x \). Then, each of the other two longer legs, being twice the shortest, can be represented as \( 2x \).
3Step 3: Write the Perimeter Equation
The perimeter of the triangle can be expressed in terms of the side lengths as follows: \[ x + 2x + 2x = 75 \]
4Step 4: Simplify the Equation
Combine like terms in the equation from the previous step: \[ 5x = 75 \]
5Step 5: Solve for \( x \)
To find \( x \), divide both sides of the equation by 5: \[ x = \frac{75}{5} = 15 \]
6Step 6: Confirm the Solution
The solution states the shortest leg is 15 meters. To confirm, check the total perimeter: \( 15 + 2(15) + 2(15) = 75 \). This confirms that the calculation is correct.
Key Concepts
Perimeter of a TriangleAlgebraic EquationsProblem Solving
Perimeter of a Triangle
The perimeter of a triangle is the total distance around the triangle. You calculate it by adding up the lengths of all three sides.
When one side is described in relation to others, as in the problem with one shortest leg and two longer legs double the length, this relationship forms the basis for setting up your equation.
- If you know the lengths of each side, simply add them together.
- The formula for the perimeter, when sides are known, is expressed as: \[ P = a + b + c \]where \(a, b,\ and \ c\) are the side lengths of the triangle.
When one side is described in relation to others, as in the problem with one shortest leg and two longer legs double the length, this relationship forms the basis for setting up your equation.
Algebraic Equations
Algebraic equations are mathematical statements that show the relationship between different quantities. They usually involve variables and constants.
In our triangle problem, we used an algebraic equation to represent the perimeter in terms of a single variable, which helps in solving for unknowns. Here's how it works:
In our triangle problem, we used an algebraic equation to represent the perimeter in terms of a single variable, which helps in solving for unknowns. Here's how it works:
- Assign a variable, such as \(x\), to the unknown quantity, like the shortest leg length.
- Express the other sides in terms of \(x\). Here, the longer sides are \(2x\) each.
- Write an equation based on the perimeter: \[ x + 2x + 2x = 75 \].
- Simplify to connect the variable with the total perimeter, making it easier to solve.
Problem Solving
Problem solving is the process of working through the details of a problem to reach a solution.
When solving math problems like our triangle perimeter example, follow these steps:
- Read and understand the problem thoroughly. Identify what is given and what needs to be found.
- Translate the words into mathematical expressions using variables and equations.
- Simplify and solve the equations step-by-step.
- Check your work; make sure the solution fits all parts of the original problem.
Other exercises in this chapter
Problem 28
Translate each phrase or sentence to a mathematical expression or equation. When fourteen is added to two times a number the result is six.
View solution Problem 28
For problems \(17-46\), find the value of each expression. $$ 2 a-6 b-3 a-a+2 b, \text { if } a=4 \text { and } b=-2 $$
View solution Problem 28
Solve each equation. Be sure to check each result. $$ 4 x+7=-17 $$
View solution Problem 28
Simplify \(\frac{\frac{5}{6}-\frac{1}{4}}{\frac{1}{12}}\).
View solution