Problem 28
Question
Expand each expression using the Binomial Theorem. $$ (a x-b y)^{4} $$
Step-by-Step Solution
Verified Answer
(ax - by)^4 = a^4 x^4 - 4a^3 b x^3 y + 6a^2 b^2 x^2 y^2 - 4a b^3 x y^3 + b^4 y^4.
1Step 1: Write down the Binomial Theorem
The Binomial Theorem states that \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \]. In this exercise, the expression is \( (ax - by)^4 \), so the theorem can be applied by considering \( a = ax \) and \( b = -by \).
2Step 2: Identify the components
Identify \( a = ax \) and \( b = -by \), and \( n = 4 \). Plug these values into the formula: \[ (ax - by)^4 = \sum_{k=0}^{4} \binom{4}{k} (ax)^{4-k} (-by)^k \].
3Step 3: Calculate each term in the summation
Calculate each term using the binomial coefficients: \[ \begin{aligned} & = \binom{4}{0}(ax)^4(-by)^0 + \binom{4}{1}(ax)^3(-by)^1 + \binom{4}{2}(ax)^2(-by)^2 + \binom{4}{3}(ax)^1(-by)^3 + \binom{4}{4}(ax)^0(-by)^4 \ & = 1 (ax)^4 + 4 (ax)^3 (-by) + 6 (ax)^2 (-by)^2 + 4 (ax) (-by)^3 + 1 (-by)^4 \ & = a^4 x^4 - 4a^3 x^3 b y + 6a^2 x^2 b^2 y^2 - 4a x b^3 y^3 + b^4 y^4 \end{aligned} \]
4Step 4: Simplify the expression
Combine the like terms and ensure signs are correct: \[ (ax - by)^4 = a^4 x^4 - 4a^3 b x^3 y + 6a^2 b^2 x^2 y^2 - 4a b^3 x y^3 + b^4 y^4 \]
Key Concepts
binomial expansionbinomial coefficientsexpressions
binomial expansion
The binomial expansion is a way to expand expressions that are raised to a power, like \( (ax - by)^4 \). It uses the Binomial Theorem to break the expression into a sum of terms.
The Binomial Theorem states: \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \]. This formula gives each term of the expansion by combining powers of \(a\) and \(b\) with coefficients that are binomial coefficients.
To use the Binomial Theorem, you:
The Binomial Theorem states: \[ (a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \]. This formula gives each term of the expansion by combining powers of \(a\) and \(b\) with coefficients that are binomial coefficients.
To use the Binomial Theorem, you:
- Identify the variables \(a\), \(b\), and \(n\).
- Use the theorem to write the expanded form.
- Calculate each term.
binomial coefficients
Binomial coefficients are the numbers that appear in the binomial expansion. They are represented as \( \binom{n}{k} \) and are sometimes called 'combinations' or 'n choose k'.
These coefficients count the number of ways to choose \(k\) items from \(n\) items, and can be found using the formula: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] For example, if you want to find \( \binom{4}{2} \):
These coefficients count the number of ways to choose \(k\) items from \(n\) items, and can be found using the formula: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] For example, if you want to find \( \binom{4}{2} \):
- Plug in the values: \( n = 4\) and \( k = 2 \).
- Calculate \(4!\), \(2!\), and \( (4-2)! \).
- Simplify: \( \binom{4}{2} = \frac{4!}{2!2!} = 6 \).
expressions
In algebra, an expression is a combination of variables, constants, and operators like +, -, etc. For example, \( (ax - by)^4 \) is an expression that involves variables \(a, b, x,\) and \( y \), and a constant exponent 4.
When asked to expand an expression using the Binomial Theorem, follow these steps:
When asked to expand an expression using the Binomial Theorem, follow these steps:
- Identify each part of the expression and any constants or variables present. For \( (ax - by)^4 \), \( a, b \, x \, y \, \text{and} 4 \).
- Rewrite the expression according to the Binomial Theorem.
- Calculate each term separately and combine them to form the expanded version. This results in terms like \( a^4 x^4, -4a^3 b x^3 y, \text{and so on} \).
Other exercises in this chapter
Problem 27
Find the indicated term in each arithmetic sequence. $$ \text { 90th term of } 3,-3,-9, \ldots $$
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Show that the statement \(" n^{2}-n+41\) is a prime number" is true for \(n=1\) but is not true for \(n=41\).
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Find the indicated term of each geometric sequence. 8th term of \(1,3,9, \ldots\)
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The given pattern continues. Write down the nth term of a sequence \(\left\\{a_{n}\right\\}\) suggested by the pattern. \(\frac{1}{1 \cdot 2}, \frac{1}{2 \cdot
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