Problem 27
Question
Find the indicated term in each arithmetic sequence. $$ \text { 90th term of } 3,-3,-9, \ldots $$
Step-by-Step Solution
Verified Answer
The 90th term is -531.
1Step 1: Identify the first term
The first term of the sequence is given as 3. Let the first term be denoted by \(a_1 = 3\).
2Step 2: Determine the common difference
The common difference \(d\) is found by subtracting the first term from the second term: \[ d = -3 - 3 = -6 \]
3Step 3: Use the formula for the nth term of an arithmetic sequence
The formula for the nth term \(a_n\) of an arithmetic sequence is given by: \[ a_n = a_1 + (n - 1) \times d \]
4Step 4: Substitute the values into the formula
Substitute the known values into the formula: \[ a_{90} = 3 + (90 - 1) \times (-6) \]
5Step 5: Simplify the expression
Calculate the expression inside the parentheses first: \[ 90 - 1 = 89 \] Then multiply by the common difference: \[ 89 \times (-6) = -534 \]Finally, add this product to the first term: \[ a_{90} = 3 - 534 = -531 \]
Key Concepts
common differencenth term formulasequence simplification
common difference
Understanding the concept of the 'common difference' in an arithmetic sequence is key to solving these problems. An arithmetic sequence is a sequence of numbers in which the difference of any two successive members is a constant, known as the common difference.
The formula for the common difference is simple: subtract any term by the one before it.
The formula for the common difference is simple: subtract any term by the one before it.
- For example: Given the sequence 3, -3, -9, ..., subtract the first term from the second term to get: \( d = -3 - 3 = -6 \)
nth term formula
The 'nth term formula' in an arithmetic sequence is a powerful tool that allows us to find any term in the sequence without having to list out all preceding terms. The formula is: \[ a_n = a_1 + (n - 1) \times d \]
Knowing these variables makes it straightforward to plug values into the formula and solve. For example, to find the 90th term of the sequence 3, -3, -9, ...:
- Where:
- \( a_n \) is the nth term we are looking for.
- \( a_1 \) is the first term.
- \( d \) is the common difference.
- \( n \) is the term position.
Knowing these variables makes it straightforward to plug values into the formula and solve. For example, to find the 90th term of the sequence 3, -3, -9, ...:
- \( a_{90} = 3 + (90 - 1) \times (-6) \)
sequence simplification
Sequence simplification involves breaking down the steps to find the nth term without unnecessary complexity. Start by identifying the required elements: the first term and the common difference. Then, use the nth term formula and follow these steps:
By systematically simplifying the expression step by step, you can confidently find any term in the sequence. This method helps eliminate mistakes and ensures a clear path to the solution.
- Substitute the known values into the formula: \[ a_{90} = 3 + (90 - 1) \times (-6) \].
- Perform the operations inside the parentheses first: \[ 90 - 1 = 89 \].
- Multiply by the common difference: \[ 89 \times (-6) = -534 \].
- Add this product to the first term: \[ 3 - 534 = -531 \].
By systematically simplifying the expression step by step, you can confidently find any term in the sequence. This method helps eliminate mistakes and ensures a clear path to the solution.
Other exercises in this chapter
Problem 27
Find the indicated term of each geometric sequence. 7th term of \(1, \frac{1}{2}, \frac{1}{4}\)
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The given pattern continues. Write down the nth term of a sequence \(\left\\{a_{n}\right\\}\) suggested by the pattern. \(\frac{1}{2}, \frac{2}{3}, \frac{3}{4},
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Show that the statement \(" n^{2}-n+41\) is a prime number" is true for \(n=1\) but is not true for \(n=41\).
View solution Problem 28
Expand each expression using the Binomial Theorem. $$ (a x-b y)^{4} $$
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