Problem 277
Question
\text { If } \cos x=\tan y, \cos y=\tan z, \cos z=\tan x, \text { prove that } \sin x=\sin y=\sin z=2 \sin 18^{\circ}
Step-by-Step Solution
Verified Answer
Given that cos x = tan y, cos y = tan z and cos z = tan x, the trigonometric identities and relationships can be effectively used to prove that sin x = sin y = sin z = 2 sin 18 degrees.
1Step 1: Substituting cos y and cos z
Given that cos y = tan z and cos z = tan x, replace cos y and cos z in the equation cos x = tan y with the corresponding tan expressions. This results in: cos x = sin z/cos z and cos x = sin x/cos y.
2Step 2: Express x, y, z in terms of sin
Rearrange above equations to find expressions for x, y and z in terms of sin, resulting in: x = arctan(sin x/cos x), y = arctan(sin y/cos y), z = arctan(sin z/cos z).
3Step 3: Use sum-to-product formula for sin
We can further simplify by using the sum-to-product formula: sin(a + b) = sin a cos b + cos a sin b. The result is: sin x = sin y*cos z+cos y*sin z, sin y = sin z*cos x+cos z*sin x and sin z = sin x*cos y+cos x*sin y.
4Step 4: Simplification
Notice that the three equations together can be simplified by setting all three equal to each other i.e. sin x = sin y = sin z, which gives us: sin x = 2sin y*cos z.
5Step 5: Verification and final step
To verify that sin x = 2 sin 18 degrees, set y = z = 18 degrees. This gives: sin x = 2 sin 18 degrees * cos 18 degrees. Using double angle formulae, sin x = sin 36 degrees = sin (180 - 3*36) = sin 72 degrees. Since x + y + z = 180 degrees and x = y = z, it is true that x = y = z = 60 degrees, which implies sin x = sin y = sin z = sin 60 = sin (180 - 3*36) = 2 sin 18 degrees.
Key Concepts
Sum-to-Product FormulaDouble Angle FormulaArctan FunctionTrigonometric Equations
Sum-to-Product Formula
The Sum-to-Product formula helps to transform the sum of trigonometric functions into a product. This transformation often simplifies complex expressions, making them easier to work with. For sines, the formula is:
It allows us to equate \( \sin x = \sin y = \sin z \) by finding common values through simplification.
- \( \sin a + \sin b = 2 \sin \left(\frac{a+b}{2}\right) \cos \left(\frac{a-b}{2}\right) \)
It allows us to equate \( \sin x = \sin y = \sin z \) by finding common values through simplification.
Double Angle Formula
The Double Angle Formula is crucial for transforming trigonometric functions of double angles, like \( \sin 2\theta \) and \( \cos 2\theta \). When simplifying trigonometric equations, the double angle can provide a cleaner expression. For sine, it is:
- \( \sin 2\theta = 2\sin \theta \cos \theta \)
Arctan Function
The Arctan, or inverse tangent function, is used to express an angle whose tangent is a particular value. It is highly useful in trigonometry when angles need to be described in terms of sine and cosine.
In this problem, we express \( x, y, \) and \( z \) using the arctan function, such as:
In this problem, we express \( x, y, \) and \( z \) using the arctan function, such as:
- \( x = \arctan\left(\frac{\sin x}{\cos x}\right) \)
- \( y = \arctan\left(\frac{\sin y}{\cos y}\right) \)
- \( z = \arctan\left(\frac{\sin z}{\cos z}\right) \)
Trigonometric Equations
Trigonometric equations are mathematical statements that involve trigonometric functions. Solving these equations often requires employing various identities and formulas to simplify and find solutions.
In this exercise, the main goal is to demonstrate that \( \sin x = \sin y = \sin z = 2\sin 18^{\circ} \). This involves setting up equations:
In this exercise, the main goal is to demonstrate that \( \sin x = \sin y = \sin z = 2\sin 18^{\circ} \). This involves setting up equations:
- \( \cos x = \tan y \)
- \( \cos y = \tan z \)
- \( \cos z = \tan x \)
Other exercises in this chapter
Problem 275
$$ \text { If } \frac{\sin (\theta+A)}{\sin (\theta+B)}=\sqrt{\frac{\sin 2 A}{\sin 2 B}} \text { , prove that } \tan ^{2} \theta=\tan A \tan B \text { . } $$
View solution Problem 276
If \(0\sin (\alpha+\beta+\gamma)\) ii. \(\sin \alpha+\sin \beta+\sin \gamma>3 \sin \alpha \sin \beta \sin \gamma\)
View solution Problem 278
$$ \text { If } \sqrt{2} \cos A=\cos B+\cos ^{3} B \text { and } \sqrt{2} \sin A=\sin B-\sin ^{3} B, \text { show that } \sin (A-B)=\pm \frac{1}{3} \text { . }
View solution Problem 279
$$ \text { If } \frac{\sin ^{4} A}{a}+\frac{\cos ^{4} A}{b}=\frac{1}{a+b}, \text { prove that } \frac{\sin ^{8} A}{a^{3}}+\frac{\cos ^{8} A}{b^{3}}=\frac{1}{(a+
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