Problem 27
Question
Solve the equation or write no real solution. Write the solutions as integers if possible. Otherwise, write them as radical expressions. $$ x^{2}=256 $$
Step-by-Step Solution
Verified Answer
The solutions to the equation are \(x = -16\) and \(x = 16\).
1Step 1: Recognize the equation type
Recognize that this is a simple quadratic equation, in which the square of a variable is equal to a constant number. In this case, the equation is \(x^{2} = 256\).
2Step 2: Take the square root
To undo the squaring operation, take the square root of both sides of the equation to solve for \(x\). Remember, when we take the square root of both sides, we must include both the positive and negative roots. So, the equation becomes: \(x = \pm \sqrt{256}\).
3Step 3: Calculate the value
Simplify the right side by calculating the square root of 256, which gives us 16. Due to the plus/minus sign in front of the square root, the solution to the equation is \(x = -16\) and \(x = 16\).
Key Concepts
Solving EquationsSquare RootInteger Solutions
Solving Equations
When faced with an equation, particularly a quadratic one like \( x^2 = 256 \), the primary goal is to determine the value of the unknown variable, in this case \( x \). Quadratic equations typically involve terms where the variable is squared.
The first step in solving such an equation is to identify its type. Recognizing a quadratic equation is crucial because it tells us that the solution involves finding the roots of the polynomial.
The first step in solving such an equation is to identify its type. Recognizing a quadratic equation is crucial because it tells us that the solution involves finding the roots of the polynomial.
- Identify the equation: Look for expressions like \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants.
- Isolate the variable term: For \( x^2 = 256 \), it's already in a form where the term involving \( x \) is isolated.
Square Root
The square root is a mathematical operation that essentially "undoes" squaring. To solve \( x^2 = 256 \), we apply the square root to both sides of the equation. This involves a few key steps.
- Understanding square roots: The square root of a number \( n \) is a value that, when multiplied by itself, gives \( n \). Thus, \( \sqrt{n} \times \sqrt{n} = n \).
- Applying square roots: When you take the square root of both sides of \( x^2 = 256 \), you must consider both the positive and negative solutions. This is because both \( 16 \times 16 \) and \( -16 \times -16 \) equal 256.
- Simplifying the result: Once \( \sqrt{256} \) is computed as 16, we know that the solutions for \( x \) are \( x = 16 \) and \( x = -16 \).
Integer Solutions
Integer solutions are solutions to an equation that are whole numbers without fractions or decimals. In the case of solving \( x^2 = 256 \), we identify if the solutions are integers.
- Verifying integer solutions: Here, \( x = 16 \) and \( x = -16 \) are both integers. They satisfy the equation perfectly as integer squares.
- Recognizing when integers occur: In cases where the squared constant, like 256, is a perfect square, the roots will often be integers. Perfect squares have integer square roots.
- Handling non-integer solutions: If square roots aren't perfect, solutions may involve radicals. For \( x^2 = 256 \), since 256 is a perfect square, the problem specifically yields integer solutions, simplifying verification and interpretation.
Other exercises in this chapter
Problem 27
Simplify the expression. $$ \sqrt{200} $$
View solution Problem 27
Evaluate the expression. Check the results by squaring each root. $$ \sqrt{196} $$
View solution Problem 28
Complete the statement with always, sometimes, or never. If \(a\) is a real number, then \(\sqrt{a^{2}}\) is ? equal to \(|a|\)
View solution Problem 28
Find the coordinates of the vertex. Make a table of values, using \(x\) -values to the left and to the right of the vertex. $$ y=-7 x^{2}+2 x $$
View solution