Problem 27
Question
Simplify the expression. $$ \sqrt{200} $$
Step-by-Step Solution
Verified Answer
The simplified expression for \( \sqrt{200} \) is \( 2\sqrt{50} \)
1Step 1: Identify the Factors
First, we need to identify the factors of the number 200 that are perfect squares. Examining the factors, we can see that 200 can be written as \(4 \times 50\). Here, 4 is a perfect square.
2Step 2: Use the Property of Square Roots
We can think of \( \sqrt{200} \) as \( \sqrt{4 \times 50} \). From the properties of square roots, we know that \( \sqrt{a \times b} \) can become \( \sqrt{a} \times \sqrt{b} \). So, \(\sqrt{200}\) becomes \( \sqrt{4} \times \sqrt{50} \).
3Step 3: Solve the Square Roots
Calculating both square roots, \( \sqrt{4} \) equals 2 and \( \sqrt{50} \) does not simplify further. Thus, we reach the simplified expression \( 2\sqrt{50} \)
Key Concepts
Perfect SquaresProperties of Square RootsFactorization in Algebra
Perfect Squares
Understanding perfect squares is fundamental when simplifying square root expressions. A perfect square is a number that can be expressed as the product of an integer with itself. For example, 16 is a perfect square because it is the product of 4 times 4, usually written as \(4^2\).
Perfect squares are critical in simplification because the square root of a perfect square is always an integer. This means that when you come across a perfect square under a square root symbol, you can easily simplify it to its integer root. In the context of our original exercise, \(4\) is a perfect square since \(2 \times 2 = 4\), which allows for simpler solutions.
Perfect squares are critical in simplification because the square root of a perfect square is always an integer. This means that when you come across a perfect square under a square root symbol, you can easily simplify it to its integer root. In the context of our original exercise, \(4\) is a perfect square since \(2 \times 2 = 4\), which allows for simpler solutions.
Properties of Square Roots
When simplifying square roots, it's essential to understand their properties. The square root function essentially asks the question: 'What number, when multiplied by itself, gives the original number?' One of the main properties used in simplification is that \(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\). This property allows us to break down complex square roots into simpler components that can be easier to evaluate.
In the exercise, this property is applied by breaking down \(\sqrt{200}\) into \(\sqrt{4} \times \sqrt{50}\), simplifying the root of the perfect square (4), and keeping the second component (\(\sqrt{50}\)) as it is not a perfect square.
In the exercise, this property is applied by breaking down \(\sqrt{200}\) into \(\sqrt{4} \times \sqrt{50}\), simplifying the root of the perfect square (4), and keeping the second component (\(\sqrt{50}\)) as it is not a perfect square.
Factorization in Algebra
Factorization is a powerful tool in algebra that involves breaking down numbers or expressions into factors that can be multiplied together to give the original number or expression. In the context of square roots, factorization helps find the perfect squares within a number, thereby simplifying the square root.
For our exercise, we used factorization to decompose 200 into \(4 \times 50\). With further factorization, if necessary, you can break down the number under the square root even more, revealing additional perfect squares that can simplify the expression further. Always look for the largest perfect square within a number to simplify square roots most efficiently.
For our exercise, we used factorization to decompose 200 into \(4 \times 50\). With further factorization, if necessary, you can break down the number under the square root even more, revealing additional perfect squares that can simplify the expression further. Always look for the largest perfect square within a number to simplify square roots most efficiently.
Other exercises in this chapter
Problem 27
Write the equation in standard form. Identify the values of a, b, and c. $$\frac{1}{3}-2 x=\frac{2}{3} x^{2}$$
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Determine whether the equation has two solutions, one solution, or no real solution. \(6 x^{2}-2 x+4=0\)
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Evaluate the expression. Check the results by squaring each root. $$ \sqrt{196} $$
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Solve the equation or write no real solution. Write the solutions as integers if possible. Otherwise, write them as radical expressions. $$ x^{2}=256 $$
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