Problem 27
Question
Show that \(f\) and \(g\) are inverse functions (a) algebraically, (b) graphically, and (c) numerically. $$f(x)=x^{3}+5, \quad g(x)=\sqrt[3]{x-5}$$
Step-by-Step Solution
Verified Answer
The functions \(f(x)=x^3+5\) and \(g(x)=\sqrt[3]{x-5}\) are indeed inverses of each other. This conclusion is based on our algebraic manipulation which yielded \(f(g(x)) = x\) and \(g(f(x)) = x\), which is the basic property of inverse functions. Their graphical representations would also reflect each other in the line \(y=x\), and a numerical check would show corresponding values across the functions.
1Step 1: Proving Algebraically
To prove two functions are inverse algebraically, we need to show that \(f(g(x)) = x\) and \(g(f(x)) = x\). \Substitute \(g(x)\) into \(f\): \\[f(g(x))= (\sqrt[3]{x-5})^3+5 = x. \]And then substitute \(f(x)\) into \(g\) : \\[g(f(x))= \sqrt[3]{(x^3+5-5)} = x.\]
2Step 2: Proving Graphically
We can visually confirm that the two functions are inverses by plotting them on the same graph. The graph of \(f(x)\) should be a reflection of the graph of \(g(x)\) about the line \(y=x\). If they are, it means they are inverse functions.
3Step 3: Proving Numerically
To prove inverse numerically, you create a table of values for \(f\) and \(g\). If \(f\) and \(g\) are inverses, every input of \(f\) corresponds to an output of \(g\), and vice versa. This means that the x-values of function \(f\) should be the y-values of the function \(g\) and the x-values of function \(g\) should be the y-values of the function \(f\). This can be checked by establishing a series of values for x, finding the corresponding y-values for each function, and checking to see if the required condition is fulfilled.
Key Concepts
Algebraic ProofGraphical RepresentationNumerical Verification
Algebraic Proof
When it comes to proving that two functions are inverses of each other algebraically, the key is to ensure that they can reverse each other’s operations. For the functions \( f(x) = x^3 + 5 \) and \( g(x) = \sqrt[3]{x - 5} \), this means verifying two conditions: whether \( f(g(x)) = x \) and \( g(f(x)) = x \).
- To find \( f(g(x)) \), substitute \( g(x) \) into \( f \): \[ f(g(x)) = \left( \sqrt[3]{x - 5} \right)^3 + 5. \] Simplifying inside the parenthesis eliminates the cube root with the cube, resulting in \( x - 5 \), and adding 5 resets it to \( x \).
- Similarly, substitute \( f(x) \) into \( g \) to find \( g(f(x)) \): \[ g(f(x)) = \sqrt[3]{(x^3 + 5) - 5} = \sqrt[3]{x^3}. \] The cube and the cube root again cancel each other, returning \( x \).
Graphical Representation
A visual way to verify if two functions are inverses involves graphing both functions on the same plane and checking their symmetry about the line \( y = x \). This line acts almost like a mirror.
- Graph \( f(x) = x^3 + 5 \), which shifts the usual cubic graph upwards by 5 units.
- Graph \( g(x) = \sqrt[3]{x - 5} \), which shifts the typical cubic root graph to the right by 5 units.
Numerical Verification
Numerically verifying inverse functions through tables of values can make their inverse relationship more tangible. This process involves computing a series of \( x \) values and comparing outputs.
- Choose sample input values such as \( x = 1, 2, 3, \ldots \).
- Compute \( f(x) \) for these values to get outputs (\( y \)-values).
- For the same \( y \)-values, calculate \( g(y) \) and check if it returns the original \( x \) values.
Other exercises in this chapter
Problem 27
Use a graphing utility to graph the function and (b) determine the open intervals on which the function is increasing, decreasing, or constant. $$f(x)=3$$
View solution Problem 27
Evaluate the indicated function for \(f(x)=x^{2}-1\) and \(g(x)=x-2\) algebraically. If possible, use a graphing utility to verify your answer. $$(f-g)(t+1)$$
View solution Problem 27
(a) use a graphing utility to graph the function and (b) determine the open intervals on which the function is increasing, decreasing, or constant. $$f(x)=3$$
View solution Problem 27
Sketch the graph of the equation. \(y=|x-2|\)
View solution