Problem 27
Question
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$-12,-8,-4,0, \dots$$
Step-by-Step Solution
Verified Answer
Common difference: 4, Fifth term: 4, \(n\)-th term: \(a_n = 4n - 16\), 100th term: 384.
1Step 1: Identify the First Term and the Second Term
The first term of the sequence is given as \(-12\) and the second term is \(-8\). The first term is often denoted as \(a_1 = -12\) and \(a_2 = -8\).
2Step 2: Calculate the Common Difference
The common difference \(d\) in an arithmetic sequence is found by subtracting the first term from the second term:\[d = a_2 - a_1 = -8 - (-12) = -8 + 12 = 4.\]So, the common difference \(d\) is \(4\).
3Step 3: Determine the Fifth Term
Use the common difference to calculate the fifth term. The formula for the \(n\)-th term of an arithmetic sequence is:\[a_n = a_1 + (n-1)d.\]For the fifth term \(a_5\):\[a_5 = a_1 + (5-1)d = -12 + 4 \times 4 = -12 + 16 = 4.\]So, the fifth term is \(4\).
4Step 4: Determine the General Formula for the \(n\)-th Term
Using the formula for the \(n\)-th term:\[a_n = a_1 + (n-1)d,\]substitute \(a_1 = -12\) and \(d = 4\) to get the formula:\[a_n = -12 + (n-1) \times 4.\]Simplify it:\[a_n = -12 + 4n - 4 = 4n - 16.\]This is the formula for the \(n\)-th term: \(a_n = 4n - 16\).
5Step 5: Determine the 100th Term
Using the general formula \(a_n = 4n - 16\), substitute \(n = 100\) to find the 100th term:\[a_{100} = 4 \times 100 - 16 = 400 - 16 = 384.\]Thus, the 100th term is \(384\).
Key Concepts
Common Differencen-th Term Formula100th Term Calculation
Common Difference
An arithmetic sequence is a series of numbers where each term increases or decreases by a constant amount, known as the common difference.
In our example with the sequence \(-12, -8, -4, 0, \ldots\), the first term is \(-12\) and the second term is \(-8\). To find the common difference, we subtract the first term from the second term:
In our example with the sequence \(-12, -8, -4, 0, \ldots\), the first term is \(-12\) and the second term is \(-8\). To find the common difference, we subtract the first term from the second term:
- \[d = a_2 - a_1 = -8 - (-12) = 4\]
n-th Term Formula
The general formula for finding any term in an arithmetic sequence is essential to work out terms beyond those given. This formula is
For our sequence, substituting \(a_1 = -12\) and \(d = 4\) gives us:
- \[a_n = a_1 + (n-1)d\]
For our sequence, substituting \(a_1 = -12\) and \(d = 4\) gives us:
- \[a_n = -12 + (n-1) \times 4\]
- \[a_n = 4n - 16\]
100th Term Calculation
To find a specific term far along in an arithmetic sequence, such as the 100th term, we can plug into the n-th term formula from the previous section. This eliminates the need to calculate each term one by one.
We use the formula:
We use the formula:
- \[a_n = 4n - 16\]
- \[a_{100} = 4 \times 100 - 16 = 384\]
Other exercises in this chapter
Problem 26
Determine the common ratio, the fifth term, and the \(n\) th term of the geometric sequence. $$1, \sqrt{2}, 2,2 \sqrt{2}, \ldots$$
View solution Problem 26
Find the \(n\) th term of a sequence whose first several terms are given. $$5,-25,125,-625, \dots$$
View solution Problem 27
Find the last two terms in the expansion of \(\left(a^{2 / 3}+a^{1 / 3}\right)^{25}\)
View solution Problem 27
F_{n}\( denotes the \)n\( th term of the Fibonacci sequence discussed in Section 11.1. Use mathematical induction to prove the statement. \)F_{3 n}\( is even fo
View solution