Problem 255
Question
In the following exercises, solve using rectangle properties. The area of a rectangle is 414 square meters. The length is 18 meters. What is the width?
Step-by-Step Solution
Verified Answer
The width is 23 meters.
1Step 1: Identify Given Information
The problem states that the area of the rectangle is 414 square meters and the length is 18 meters.
2Step 2: Recall the Formula for Area of a Rectangle
The formula for the area of a rectangle is: \[ \text{Area} = \text{Length} \times \text{Width} \]
3Step 3: Substitute the Given Values
Substitute the given values into the area formula: \[ 414 = 18 \times \text{Width} \]
4Step 4: Solve for the Width
To find the width, divide both sides of the equation by 18: \[ \text{Width} = \frac{414}{18} \]
5Step 5: Simplify the Calculation
Perform the division to solve for the width: \[ \text{Width} = 23 \]
Key Concepts
Area of a RectangleAlgebraic EquationGeometry
Area of a Rectangle
Understanding the area of a rectangle is essential in solving many geometry problems. The area represents the amount of space inside the rectangle, and it is measured in square units, such as square meters. The formula to calculate the area is:
\[ \text{Area} = \text{Length} \times \text{Width} \]
In this formula:
\[ \text{Area} = \text{Length} \times \text{Width} \]
In this formula:
- Length is the longer side of the rectangle.
- Width is the shorter side of the rectangle.
Algebraic Equation
Algebraic equations often show up when solving geometry problems. An equation is a mathematical statement that asserts the equality of two expressions. In this exercise, by knowing the area and the length, we form an equation to find the width:
\[ 414 = 18 \times \text{Width} \]
This is a simple algebraic equation where you solve for the unknown width. Here's how to solve such an equation step-by-step:
\[ 414 = 18 \times \text{Width} \]
This is a simple algebraic equation where you solve for the unknown width. Here's how to solve such an equation step-by-step:
- Isolate the variable (Width) by performing inverse operations.
- Divide both sides by 18: \[ \text{Width} = \frac{414}{18} \]
- Simplify the result to get the value for Width.
Geometry
Geometry involves studying shapes, sizes, and the properties of space. Solving problems like the one in our exercise helps you understand important geometric concepts. Rectangles, in particular, are foundational shapes in geometry.
Important attributes of rectangles include:
In our example, knowing the dimensions and properties of rectangles allows us to calculate unknown measures. As a result, we find the width by working through algebraic equations grounded in geometric principles.
Important attributes of rectangles include:
- Opposite sides are equal in length.
- Each angle is a right angle (90 degrees).
In our example, knowing the dimensions and properties of rectangles allows us to calculate unknown measures. As a result, we find the width by working through algebraic equations grounded in geometric principles.
Other exercises in this chapter
Problem 253
In the following exercises, solve using rectangle properties. A rectangular room is 15 feet wide by 14 feet long. What is its perimeter?
View solution Problem 254
In the following exercises, solve using rectangle properties. A driveway is in the shape of a rectangle 20 feet wide by 35 feet long. What is its perimeter?
View solution Problem 256
In the following exercises, solve using rectangle properties. The area of a rectangle is 782 square centimeters. The width is 17 centimeters. What is the length
View solution Problem 257
In the following exercises, solve using rectangle properties. The width of a rectangular window is 24 inches. The area is 624 square inches. What is the length?
View solution