Problem 25
Question
Write in standard form an equation of the line that passes through the given point and has the given slope. \((3,-2), m=5\)
Step-by-Step Solution
Verified Answer
The standard form of the equation of the line passing through the point (3,-2) with a slope of 5 is -5x + y = -17.
1Step 1: Determine the y-intercept
Using the formula \(y = mx + c\), substitute the given point and slope into this equation to determine the y-intercept. The point given is (3, -2), and slope is 5, so the equation becomes -2 = 5*(3) + c. Solving for c gives c = -2 - 5*3 = -17.
2Step 2: Write the equation of the line
Now, using the slope and calculated y-intercept, we can substitute into \(y = mx + c\), which gives the equation of the line in slope-intercept form: \(y = 5x - 17\)
3Step 3: Convert the equation into standard form
Converting the equation into standard form (Ax + By = C), we move all terms except the constant to the left side of the equation: -5x + y = -17
Key Concepts
Slope-Intercept FormFinding Y-InterceptLinear Equations
Slope-Intercept Form
The slope-intercept form is a way of writing the equation of a straight line. It's expressed as \( y = mx + c \), where \( m \) represents the slope of the line and \( c \) is the y-intercept, which is where the line crosses the y-axis. This form is particularly useful because it easily showcases the rate of change of y with respect to x, which is the definition of the slope, and the starting value when x is zero, the y-intercept. It simplifies graphing linear equations and understanding their behaviors.
For example, if a problem gives you the slope of a line and a point through which the line passes, you can substitute the point values into the slope-intercept form to find the y-intercept. Once you have both the slope and y-intercept, you can graph the line or use it in calculations, positioning the line in the coordinate system with clarity and ease.
For example, if a problem gives you the slope of a line and a point through which the line passes, you can substitute the point values into the slope-intercept form to find the y-intercept. Once you have both the slope and y-intercept, you can graph the line or use it in calculations, positioning the line in the coordinate system with clarity and ease.
Finding Y-Intercept
To find the y-intercept of a line, you need to know the slope of the line and a point through which it passes. The y-intercept is the value of \( y \) when \( x \) is zero. You can find it by using the slope-intercept equation \( y = mx + c \).
Start with solving for \( c \), by plugging the point's coordinates \((x_1, y_1)\) into the equation and using the given slope \( m \), to get \( y_1 = mx_1 + c \). After arranging the terms, you can determine the value of \( c \) and thus have discovered the point where your line crosses the y-axis.
For instance, in the given exercise, substituting the point (3, -2) and the slope 5 into the equation gives us -2 = 5(3) + c, which simplifies to find the y-intercept \( c = -17 \). This shows the versatility and practicality of the slope-intercept form in not only understanding but also quickly finding crucial characteristics of a line.
Start with solving for \( c \), by plugging the point's coordinates \((x_1, y_1)\) into the equation and using the given slope \( m \), to get \( y_1 = mx_1 + c \). After arranging the terms, you can determine the value of \( c \) and thus have discovered the point where your line crosses the y-axis.
For instance, in the given exercise, substituting the point (3, -2) and the slope 5 into the equation gives us -2 = 5(3) + c, which simplifies to find the y-intercept \( c = -17 \). This shows the versatility and practicality of the slope-intercept form in not only understanding but also quickly finding crucial characteristics of a line.
Linear Equations
Linear equations form the backbone of algebra and appear as the functions that graph to straight lines. A linear equation in two variables typically looks like \( Ax + By = C \), where A, B, and C are constants, and x and y are variables. This form is known as the standard form of a linear equation.
The beauty of linear equations lies in their predictability and simplicity. They model relationships with a constant rate of change, which is valuable in various scientific, economic, and social contexts.
As part of moving from the slope-intercept form to the standard form, you might need to rearrange terms. For example, the line equation \( y = 5x - 17 \) from our solution converts to standard form by moving all variables to one side of the equation, resulting in \( -5x + y = -17 \). In this form, A equals -5, B equals 1, and C equals -17. The standard form is preferred for certain practical applications, like when establishing constraints in optimization problems or solving systems of equations.
The beauty of linear equations lies in their predictability and simplicity. They model relationships with a constant rate of change, which is valuable in various scientific, economic, and social contexts.
As part of moving from the slope-intercept form to the standard form, you might need to rearrange terms. For example, the line equation \( y = 5x - 17 \) from our solution converts to standard form by moving all variables to one side of the equation, resulting in \( -5x + y = -17 \). In this form, A equals -5, B equals 1, and C equals -17. The standard form is preferred for certain practical applications, like when establishing constraints in optimization problems or solving systems of equations.
Other exercises in this chapter
Problem 25
Write in point-slope form the equation of the line that passes through the given point and has the given slope. $$ (-3,4), m=6 $$
View solution Problem 25
Write in slope-intercept form the equation of the line passing through the two points. Show that the line is perpendicular to the given line. Check your answer
View solution Problem 26
Write in point-slope form the equation of the line. Then rewrite the equation in slope-intercept form. $$ (12,2), m=-7 $$
View solution Problem 26
Write in standard form an equation of the line that passes through the given point and has the given slope. \((10,6), m=0\)
View solution