Problem 25
Question
Use the square root property to solve each equation. $$ (x+3)^{2}+8=0 $$
Step-by-Step Solution
Verified Answer
No real solution.
1Step 1: Isolate the squared term
Begin by subtracting 8 from both sides of the equation to isolate the square term. This results in the equation: \( (x+3)^2 = -8 \).
2Step 2: Identify the impossibility
Recognize that you cannot take the square root of a negative number in the set of real numbers without involving imaginary numbers. This means there is no real solution to the equation.
3Step 3: Confirm understanding with imaginary numbers (optional)
If you were to proceed considering imaginary numbers, you would take the square root of both sides: \( x + 3 = \pm i\sqrt{8} \). However, this requires understanding complex numbers, often not covered in basic algebra. Conclude that there are no real numbers that satisfy this equation.
Key Concepts
Isolating Squared TermsImaginary NumbersComplex Numbers
Isolating Squared Terms
When working with equations that involve squared expressions, such as \((x + 3)^2 + 8 = 0\), the first step in solving is isolating the squared term. This involves removing any constants or terms not directly attached to the square. Here’s how to do it:
- Subtract the constant on the same side as the squared term from both sides of the equation. In this case, subtract 8 from both sides to obtain \((x + 3)^2 = -8\).
Imaginary Numbers
Imaginary numbers come into play when dealing with the square root of negative numbers. In the standard number line of real numbers, squaring any number—whether positive or negative—results in a positive number or zero. Thus, the square root of a negative number doesn't exist in the real number realm.
- An imaginary number is defined as the square root of \(-1\) and is denoted as \(i\). Thus, \(i^2 = -1\).
- If you encounter a square root of a negative number, convert this into a multiple of \(i\). For example, the square root of \(-8\) can be expressed as \(i\sqrt{8}\).
Complex Numbers
Complex numbers combine real and imaginary numbers into a single entity, represented as \(a + bi\), where \(a\) is the real part and \(bi\) is the imaginary part. The concept of complex numbers is essential in advanced algebra and beyond, particularly in solving polynomial equations that have no real solutions.
- In the equation \((x + 3)^2 = -8\), recognizing the need to use imaginary numbers leads to solutions in the form of complex numbers. Taking the square root of both sides gives \(x + 3 = \pm i\sqrt{8}\).
- To simplify, solve for \(x\) by subtracting 3 from both sides: \(x = -3 \pm i\sqrt{8}\).
Other exercises in this chapter
Problem 25
Solve. Write the solution set in interval notation. $$ \frac{x+2}{x-3}
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Find the vertex of the graph of each quadratic function. Determine whether the graph opens upward or downward, find any intercepts, and graph the function. $$ f
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Graph each quadratic function. Label the vertex and sketch and label the axis of svmmetrv. $$ H(x)=2 x^{2} $$
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Use the quadratic formula to solve each equation. These equations have real solutions and complex, but not real, solutions. $$ x(x+6)=2 $$
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