Problem 25
Question
Graph each quadratic function. Label the vertex and sketch and label the axis of svmmetrv. $$ H(x)=2 x^{2} $$
Step-by-Step Solution
Verified Answer
The vertex is at (0,0), the axis of symmetry is x=0, and the parabola opens upwards.
1Step 1: Identify the Coefficients
The quadratic function given is written in the form \( H(x) = ax^2 + bx + c \). Here, \( a = 2 \), \( b = 0 \), and \( c = 0 \).
2Step 2: Find the Vertex
The vertex of the parabola given by \( H(x) = ax^2 + bx + c \) can be calculated using the formula \( x = -\frac{b}{2a} \). For our function, \( b = 0 \) and \( a = 2 \), so \( x = -\frac{0}{4} = 0 \). Substitute back into \( H(x) \) to get \( H(0) = 2(0)^2 = 0 \). Therefore, the vertex is at the point \( (0,0) \).
3Step 3: Determine the Axis of Symmetry
The axis of symmetry for a quadratic function is always a vertical line passing through the x-value of the vertex. Here, since the vertex is at \( (0,0) \), the axis of symmetry is the line \( x = 0 \).
4Step 4: Sketch the Graph
This function represents a parabola that opens upwards because \( a = 2 > 0 \). Plot the vertex at \( (0,0) \), and choose points on either side of the vertex to determine the shape of the parabola. For example, at \( x = 1 \), \( H(1) = 2(1)^2 = 2 \), and at \( x = -1 \), \( H(-1) = 2(-1)^2 = 2 \). Plot these points and draw the parabola, making sure it's symmetric about the axis \( x = 0 \).
5Step 5: Label the Graph
Label the vertex on the graph as \( (0,0) \) and the axis of symmetry as the line \( x=0 \).
Key Concepts
Vertex CalculationAxis of SymmetryParabolaQuadratic CoefficientsUpward Opening Parabola
Vertex Calculation
In the context of quadratic functions, the vertex is a critical point where the graph changes direction. Calculating the vertex provides important insights for graphing the parabola. The given quadratic function is in the form \( H(x) = ax^2 + bx + c \). The vertex \( x \)-coordinate is found using the formula:
- \( x = -\frac{b}{2a} \)
- \( x = -\frac{0}{4} = 0 \)
- \( H(0) = 2(0)^2 = 0 \)
Axis of Symmetry
The axis of symmetry of a parabola is a vertical line that divides it into two mirror-image halves. Understanding this axis helps in making an accurate sketch of the quadratic graph.The line of symmetry can be found using the vertex \( x \)-coordinate. For a quadratic equation \( ax^2 + bx + c \), the axis of symmetry is given by:
- \( x = -\frac{b}{2a} \)
- \( x = 0 \)
Parabola
A parabola is the graph of a quadratic function and is known for its unique U-shape. In this exercise, the function \( H(x) = 2x^2 \) is a classic example of such a curve.Here are some key features of parabolas:
- The vertex is the tip of the parabola, which we calculated to be at \((0, 0)\).
- Parabolas can open upwards or downwards.
Quadratic Coefficients
The coefficients in a quadratic function determine the shape and position of the parabola. For the function \( H(x) = ax^2 + bx + c \), the values of \( a \), \( b \), and \( c \) each play roles:
- \( a \): Determines the direction and width of the parabola. If \( a > 0 \), the parabola opens upwards; if \( a < 0 \), it opens downwards. Larger \( |a| \) values mean a narrower parabola.
- \( b \): Affects the position of the vertex along the x-axis.
- \( c \): Represents the y-intercept, the point where the parabola crosses the y-axis.
- \( a = 2 \): Since \( a \) is positive, the parabola opens upwards and is relatively narrow.
- \( b = 0 \) and \( c = 0 \): Together, they make the vertex lie at the origin \((0, 0)\), giving a symmetrical graph.
Upward Opening Parabola
An upward opening parabola is one of two possible orientations of a parabola, characterized by its open end facing upwards. The function \( H(x) = 2x^2 \) serves as a perfect example of this type.The essential properties of an upward opening parabola include:
- The value of \( a > 0 \) determines this orientation, making the arms of the parabola rise as you move away from the vertex.
- The vertex is a minimum point on the graph, indicating the lowest y-value on the parabola.
Other exercises in this chapter
Problem 25
Find the vertex of the graph of each quadratic function. Determine whether the graph opens upward or downward, find any intercepts, and graph the function. $$ f
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Use the square root property to solve each equation. $$ (x+3)^{2}+8=0 $$
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Use the quadratic formula to solve each equation. These equations have real solutions and complex, but not real, solutions. $$ x(x+6)=2 $$
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Solve. Write the solution set in interval notation. $$ \frac{x-1}{x+4}>2 $$
View solution