Problem 25
Question
Solve the rational equation. Check your solutions. $$\frac{2 x}{x-1}-\frac{3}{x}=2$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \( x = 3 \).
1Step 1: Combine Like Terms
Combine like terms on one side of the equal equation. To do this, the equation can be rewritten as \( \frac{2x}{x-1} - \frac{3}{x} - 2 = 0 \).
2Step 2: Find a Common Denominator
The next step will be to find a common denominator between \(x-1\) and \(x\), which is \(x(x-1)\). Multiply the entire equation by the common denominator in order to eliminate fractions. The equation becomes: \(2x^2 - 3(x-1) - 2x(x-1) = 0 \).
3Step 3: Simplify the Equation
Simplify the equation by performing the necessary operations. The equation becomes: \(2x^2 - 3x + 3 - 2x^2 + 2x = 0\). Combine like terms to get: \( -x + 3 = 0 \).
4Step 4: Solve for the variable
Now, isolate \(x\) by subtracting subtract 3 from both sides to get: \( -x = -3 \). Then multiply by -1 to get: \( x = 3 \).
5Step 5: Check the Solution
Substitute \(x = 3\) back into the original equation to see if both sides become equal: \( \frac{2(3)}{3-1} - \frac{3}{3} = 2 \Rightarrow 3 - 1 = 2. \) Since the solution checks, \(x = 3\) is a valid solution.
Key Concepts
Common DenominatorSolving Rational EquationsVerifying Solutions
Common Denominator
When solving rational equations, finding a common denominator is crucial. Rational equations contain fractions with different denominators. To simplify and solve these equations, you need a shared denominator.
In the given exercise, the rational equation has terms like \( \frac{2x}{x-1} \) and \( \frac{3}{x} \). Here, the common denominator is \( x(x-1) \).
In the given exercise, the rational equation has terms like \( \frac{2x}{x-1} \) and \( \frac{3}{x} \). Here, the common denominator is \( x(x-1) \).
- Multiply each term by this common denominator to clear the fractions.
- This transforms the expression into a polynomial equation, making it easier to solve.
Solving Rational Equations
After finding a common denominator, the next step is solving the rational equation. The aim is to simplify the transformed equation to isolate the variable.
For our equation, \( 2x^2 - 3(x-1) - 2x(x-1) = 0 \), you simplify by expanding and combining like terms. This gives:
Solving these equations may vary in complexity, but systematically reducing and simplifying is key.
For our equation, \( 2x^2 - 3(x-1) - 2x(x-1) = 0 \), you simplify by expanding and combining like terms. This gives:
- \( 2x^2 - 3x + 3 - 2x^2 + 2x = 0 \)
- Combine to get \( -x + 3 = 0 \)
Solving these equations may vary in complexity, but systematically reducing and simplifying is key.
Verifying Solutions
Verifying solutions is an essential final step in solving rational equations. After finding a solution, substitute it back into the original equation to ensure correctness.
For \( x = 3 \), substitute back into \( \frac{2(3)}{3-1} - \frac{3}{3} \):
For \( x = 3 \), substitute back into \( \frac{2(3)}{3-1} - \frac{3}{3} \):
- Calculate to verify both sides equal 2.
- If they match, \( x = 3 \) is confirmed as correct.
Other exercises in this chapter
Problem 24
Factor to find the \(x\)-intercepts of the parabola described by the quadratic function. Also find the real zeros of the function. $$f(x)=6 x^{2}-x-2$$
View solution Problem 25
Solve the inequality by factoring. $$10 x^{2} \leq-13 x+3$$
View solution Problem 25
In Exercises \(17-40,\) let \(f(x)=-x^{2}+x, g(x)=\frac{2}{x+1},\) and \(h(x)=-2 x+1 .\) Evaluate each of the following. $$(g-h)(-2)$$
View solution Problem 25
Identify the underlying basic function, and use transformations of the basic function to sketch the graph of the given function. $$f(x)=|2 x|$$
View solution