Problem 24
Question
Factor to find the \(x\)-intercepts of the parabola described by the quadratic function. Also find the real zeros of the function. $$f(x)=6 x^{2}-x-2$$
Step-by-Step Solution
Verified Answer
The x-intercepts of the parabola described by the function \(f(x)=6x^{2}-x-2\) are (-2/3, 0) and (1/2, 0). Also, the real zeros of this function are \(x=-2/3\) and \(x=1/2\).
1Step 1: Factor the Quadratic Equation
Start by factoring the quadratic function \(f(x)=6x^{2}-x-2\). This function forms a quadratic equation of the form \(ax^{2}+bx+c=0\), where \(a=6\), \(b=-1\), and \(c=-2\). The quadratic equation can be factored by looking for two numbers that multiply to give \(ac = 6*(-2) = -12\) (the product of \(a\) and \(c\)) and that add to give \(b=-1\) (the coefficient of \(x\)). These two numbers are -3 and 4. Rewrite the equation as \(6x^{2}-3x+4x-2=0\). Then, factor by grouping: \(3x(2x-1) +2(2x-1)= 0\). This gives the factored form of the quadratic function as \((3x+2)(2x-1)=0\).
2Step 2: Find the x-intercepts
The x-intercepts are points on the graph where \(y=0\). When \(y=0\), the factored equation becomes \(0= (3x+2)(2x-1)\). Using the zero-product property, we set each factor equal to zero and solve for \(x\). So, \(3x+2=0\) gives \(x=-2/3\) and \(2x-1=0\) gives \(x = 1/2\). So, the x-intercepts of the graph of this function are (-2/3, 0) and (1/2, 0).
3Step 3: Find the real zeros of the function
The real zeros of a function are the x-coordinates where the function value is zero. These are the same as the x-intercepts for functions that cross the x-axis. So, in this case, the real zeros of the function are \(x=-2/3\) and \(x = 1/2\)
Key Concepts
x-interceptsreal zerosquadratic functions
x-intercepts
The x-intercepts of a quadratic function are critical points where the graph crosses the x-axis. These occur where the output or the y-value is zero. To find the x-intercepts for a function like \(f(x)=6x^{2}-x-2\), we need to set \(f(x)\) to zero and solve for \(x\).
This involves factoring the quadratic expression first. In our example, the function has been rewritten as \((3x+2)(2x-1)=0\). By setting each factor equal to zero, \(3x+2=0\) and \(2x-1=0\), we can solve for the x-values:
This involves factoring the quadratic expression first. In our example, the function has been rewritten as \((3x+2)(2x-1)=0\). By setting each factor equal to zero, \(3x+2=0\) and \(2x-1=0\), we can solve for the x-values:
- For \(3x+2=0\), subtract 2 and divide by 3 to get \(x=-\frac{2}{3}\).
- For \(2x-1=0\), add 1 and divide by 2 to get \(x=\frac{1}{2}\).
real zeros
Real zeros of a quadratic function are the x-values for which the function equals zero. These are also known as roots. They represent the solutions to the quadratic equation when set to zero.
For the function \(f(x)=6x^{2}-x-2\), after factoring we get \((3x+2)(2x-1)=0\). Solving each factor for zero, we find the real zeros:
These real zeros \(-\frac{2}{3}\) and \(\frac{1}{2}\) are exactly where the graph crosses the x-axis, confirming the x-values at which the parabola's value is zero. For quadratic functions, real zeros are an important feature, providing insights into the graph's behavior.
For the function \(f(x)=6x^{2}-x-2\), after factoring we get \((3x+2)(2x-1)=0\). Solving each factor for zero, we find the real zeros:
- \(3x+2=0\) gives \(x=-\frac{2}{3}\).
- \(2x-1=0\) gives \(x=\frac{1}{2}\).
These real zeros \(-\frac{2}{3}\) and \(\frac{1}{2}\) are exactly where the graph crosses the x-axis, confirming the x-values at which the parabola's value is zero. For quadratic functions, real zeros are an important feature, providing insights into the graph's behavior.
quadratic functions
Quadratic functions are a fundamental component in algebra, defined by the standard form \(f(x) = ax^2 + bx + c\). Here, \(a\), \(b\), and \(c\) are constants, with \(a\) not equal to zero. This type of function produces a parabola when graphed.
Key aspects of quadratic functions include:
Key aspects of quadratic functions include:
- The coefficient \(a\) influences the direction of the parabola. If \(a > 0\), the parabola opens upwards. If \(a < 0\), it opens downwards.
- The vertex is the highest or lowest point of the parabola, providing valuable information about the function's minimum or maximum values.
- They can have zero, one, or two real zeros, which correspond to the x-values where the function equals zero.
Other exercises in this chapter
Problem 24
In Exercises \(17-40,\) let \(f(x)=-x^{2}+x, g(x)=\frac{2}{x+1},\) and \(h(x)=-2 x+1 .\) Evaluate each of the following. $$(f-g)(-3)$$
View solution Problem 24
Identify the underlying basic function, and use transformations of the basic function to sketch the graph of the given function. $$h(x)=-\frac{1}{3}(x-2)^{2}-\f
View solution Problem 25
Solve the inequality by factoring. $$10 x^{2} \leq-13 x+3$$
View solution Problem 25
Solve the rational equation. Check your solutions. $$\frac{2 x}{x-1}-\frac{3}{x}=2$$
View solution