Problem 25
Question
Exercises \(17-30\) contain equations with constants in denominators. Solve each equation. $$ \frac{x+3}{6}=\frac{3}{8}+\frac{x-5}{4} $$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x=\frac{33}{2}\).
1Step 1: Simplify the equation
Multiply each term in the equation by the least common denominator, which is 24. This gives, \[24*(\frac{x+3}{6})=24*(\frac{3}{8})+24*(\frac{x-5}{4})\]
2Step 2: Solve the equation
Solving the equation gives, \(4(x+3)=9+6(x-5)\)
3Step 3: Distribute and combine like terms
Distribute 4 and 6 to the terms within parentheses and you get, \(4x+12=9+6x-30\). Then, rearrange terms to one side the equation to get \(2x=33\).
4Step 4: Solve for x
Finally, to isolate x, divide both sides of the equation by 2. This gives, \(x=\frac{33}{2}\).
Key Concepts
Solving EquationsLeast Common DenominatorDistributing ConstantsCombining Like Terms
Solving Equations
Solving equations can seem daunting, but once you break them down step by step, it becomes more manageable. The goal is to find the value of the unknown variable, often expressed as 'x', that makes the equation true. In this particular exercise, we started with a rational equation which involves fractions. Here's a simple breakdown:
- First, simplify the equation as much as possible.
- Next, rearrange terms to get all terms containing the variable on one side of the equation and constants on the other.
- Simplify further if possible, to easily determine the solution.
Least Common Denominator
When dealing with rational equations, combining fractions efficiently is key to finding solutions swiftly. To do this, we use the Least Common Denominator (LCD). The LCD is the smallest number that is a multiple of each of the denominators in the equation. It's like finding a common floor to bring all the fractions down to.
- Identify the denominators in your equation. For example, in our problem, we had 6, 8, and 4.
- Determine the smallest number that is evenly divisible by all these denominators. Here, the LCD is 24.
- Multiply each term in the equation by the LCD to eliminate the fractions, simplifying further manipulation of the equation.
Distributing Constants
Once fractions are eliminated, you often face expressions that need distribution, a process where you multiply a constant across terms within parentheses. Let's illustrate how this works using our exercise:
- We had to distribute 4 across \(x + 3\), yielding 4x + 12.
- Similarly, 6 had to be distributed across \(x - 5\), resulting in 6x - 30.
Combining Like Terms
In the process of solving equations, combining like terms is like organizing your notes. It helps in simplifying an equation, preparing it for the final steps of solving. Here's how we did it:
- We aligned similar terms on both sides of the equation: constants with constants, variables with variables. This reduces complexity.
- Our equation, 4x + 12 = 9 + 6x - 30, became easier to manage. By subtracting 6x from both sides and simplifying constants, we derived 2x = 33.
Other exercises in this chapter
Problem 25
In Exercises 13-26, express each interval in terms of an inequality and graph the interval on a number line. $$(-\infty, 5.5)$$
View solution Problem 25
The formula $$ \frac{W}{2}-3 H=53 $$ models the recommended weight \(W\), in pounds, for a male, where \(H\) represents the man's height, in inches, over 5 feet
View solution Problem 26
In Exercises \(21-28,\) divide and express the result in standard form. $$\frac{-6 i}{3+2 i}$$
View solution Problem 26
Solve each quadratic inequality in Exercises \(1-28\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ -x^{2
View solution