Problem 24
Question
Write in slope-intercept form the equation of the line passing through the two points. Show that the line is perpendicular to the given line. Check your answer by graphing both lines. $$ (1,9),(9,9) ; x=1 $$
Step-by-Step Solution
Verified Answer
The equation of the line passing through the points (1,9) and (9,9) is \(y = 9\). The lines \(y = 9\) and \(x = 1\) are perpendicular to each other. This is confirmed by a graphical representation.
1Step 1: Find the Equation of the Line Through the Points
The formula of the slope for two given points \((x_1, y_1)\) and \((x_2, y_2)\) is \(m = \frac{{y_2 - y_1}}{{x_2 - x_1}}\). The given points are (1,9) and (9,9). So, the slope \(m = \frac{{9 - 9}}{{9 - 1}} = 0\). The intercept form of the equation of a line is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. Here, the line passes through the points (1,9), so if we put \(x=1, y=9\), and \(m=0\) in the equation, we can solve for \(b\). Doing that, we get \(9 = 0*1 + b\), so \(b = 9\). So the equation of the line is \(y = 0*x + 9\), which simplifies to \(y = 9\).
2Step 2: Show the Line is Perpendicular to the Given Line
Two lines are perpendicular if the product of their slopes is -1. The given line is \(x=1\), which is a vertical line and its slope is undefined. The slope of the line we found in step 1 is 0. The product of an undefined value (which can be thought of as infinity) and zero is undefined, but in this context, we say it is -1. So, the lines are indeed perpendicular.
3Step 3: Graph the Lines
Both lines can be graphed on a coordinate plane. Line 1: \(y = 9\) is a horizontal line running through the point where \(y = 9\). Line 2: \(x = 1\) is a vertical line running through the point where \(x = 1\). As expected, the lines intersect at right angles, which confirms they are perpendicular.
Key Concepts
Equation of a LinePerpendicular LinesGraphing Lines
Equation of a Line
The equation of a line is a fundamental concept in algebra and geometry. It represents all the possible points that a straight line contains on a coordinate plane. The most commonly used form for the equation of a line is the slope-intercept form, given by:\[ y = mx + b \]where:
- \( m \) is the slope of the line, which tells us how steep the line is.
- \( b \) is the y-intercept, which is the point where the line crosses the y-axis.
Perpendicular Lines
Perpendicular lines intersect at a right angle, which is 90 degrees. The concept of perpendicularity in terms of slopes is that their slopes multiply to give -1, except when dealing with vertical or horizontal lines.Vertical lines have an "undefined" slope, while horizontal lines have a slope of 0. When examining whether the line \( y = 9 \) (horizontal) is perpendicular to the line \( x = 1 \) (vertical):
- The product of an undefined slope and zero is not a straightforward calculation.
- However, by geometric interpretation, a vertical and a horizontal line are inherently perpendicular.
Graphing Lines
Graphing lines effectively helps to visualize the relationships and intersections between different lines on a plane. Let’s graph our lines from the exercise:### Horizontal Line: \( y = 9 \)- This line runs parallel to the x-axis and crosses the y-axis at \( y = 9 \).- Every point on this line has a y-coordinate of 9.### Vertical Line: \( x = 1 \)- This line runs parallel to the y-axis and crosses the x-axis at \( x = 1 \).- Every point on this line has an x-coordinate of 1.When these two lines are plotted on the same graph, they should intersect at the point (1,9), where \( x = 1 \) meets \( y = 9 \).
This intersection forms a right angle, confirming that these lines are perpendicular as checked algebraically. Graphing is a powerful tool to validate algebraic calculations visually and helps in understanding how different elements on a coordinate plane interact.
This intersection forms a right angle, confirming that these lines are perpendicular as checked algebraically. Graphing is a powerful tool to validate algebraic calculations visually and helps in understanding how different elements on a coordinate plane interact.
Other exercises in this chapter
Problem 23
Write in standard form an equation of the line that passes through the given point and has the given slope. \((-1,4), m=-3\)
View solution Problem 24
Write in point-slope form the equation of the line that passes through the given point and has the given slope. $$ (-4,3), m=-6 $$
View solution Problem 24
Write in standard form an equation of the line that passes through the given point and has the given slope. \((-6,-7), m=-1\)
View solution Problem 25
Write in point-slope form the equation of the line that passes through the given point and has the given slope. $$ (-3,4), m=6 $$
View solution