Problem 24
Question
Use the formula for \(S_{n}\) to find the sum of the first five terms for each geometric sequence. Round the answers for Exercises 25 and 26 to the nearest hundredth. $$12,-4, \frac{4}{3},-\frac{4}{9}, \dots$$
Step-by-Step Solution
Verified Answer
The sum of the first five terms is approximately 9.04.
1Step 1: Identify Geometric Sequence Elements
A geometric sequence is defined by the first term (\(a_1\)) and the common ratio (\(r\)). For the sequence given (\(12, -4, \frac{4}{3}, -\frac{4}{9}, \ldots\)), the first term \(a_1 = 12\).
2Step 2: Determine Common Ratio
The common ratio \(r\) is found by dividing the second term by the first term: \(-4 \div 12 = \frac{-1}{3}\).
3Step 3: Apply Sum Formula for Sn
The sum of the first \(n\) terms of a geometric sequence is given by the formula: \[S_n = a_1 \frac{1 - r^n}{1 - r}\] Substitute \(n = 5\), \(a_1 = 12\), and \(r = -\frac{1}{3}\).
4Step 4: Calculate \(r^n\)
Find \((-\frac{1}{3})^5\). Since \((-\frac{1}{3})^5 = -\frac{1}{243}\), the value is needed for the next calculation.
5Step 5: Plug Values into Formula
Substitute the values into the sum formula: \[S_5 = 12 \frac{1 - (-\frac{1}{243})}{1 - (-\frac{1}{3})}\].
6Step 6: Simplify the Expression
Calculate the expression: \[1 - (-\frac{1}{243}) = \frac{244}{243}\] and \[1 + \frac{1}{3} = \frac{4}{3}\]. Substitute back: \[S_5 = 12 \frac{\frac{244}{243}}{\frac{4}{3}}\].
7Step 7: Final Calculation
Multiply and simplify the expression: \[S_5 = 12 \times \frac{244}{243} \times \frac{3}{4} = 9.04\] (rounded to the nearest hundredth).
Key Concepts
Sum Formula for Geometric SequenceCommon RatioGeometric Series
Sum Formula for Geometric Sequence
When calculating the sum of the first few terms in a geometric sequence, we use a special formula. The sum formula for the first \(n\) terms of a geometric sequence is expressed as:\[S_n = a_1 \frac{1 - r^n}{1 - r}\]where \(a_1\) is the first term, \(r\) is the common ratio, and \(n\) is the number of terms you want to sum. This formula derives from the pattern of multiplying each term by the common ratio. It's helpful because it allows you to calculate large sums quickly without manually adding each term.
- \(S_n\): sum of the first \(n\) terms
- \(a_1\): first term of the sequence
- \(r\): common ratio
- \(n\): number of terms in the sequence
Common Ratio
In any geometric sequence, each term after the first is obtained by multiplying the previous term by a fixed, non-zero number called the "common ratio". This ratio, denoted as \(r\), is a key element of the sequence's structure. To find the common ratio, simply divide any term in the sequence by the term that comes just before it.
- Formula to calculate \(r\): \(r = \frac{a_2}{a_1}\)
- \(a_2\): second term
- \(a_1\): first term
Geometric Series
A geometric series is the sum of the terms of a geometric sequence. When dealing with a finite series, we can find the sum using the sum formula explained earlier. A key characteristic of a geometric series is that each term is a constant multiple of the preceding term; this constant is known as the common ratio. Consider the geometric series formed by the sequence \(12, -4, \frac{4}{3}, -\frac{4}{9}, \ldots\). Here, you're adding these numbers together to find the sum of the first few terms, which is a common task in math courses.
- Finite geometric series have a set number of terms.
- The sum of the series is what distinguishes it from just listing the sequence.
Other exercises in this chapter
Problem 23
Find the first four terms of each sequence. $$a_{1}=1, a_{2}=1, a_{n}=a_{n-1}+a_{n-2}, \text { for } n \geq 3$$ (the Fibonacci sequence)
View solution Problem 24
Find \(a_{8}\) and \(a_{n}\) for each arithmetic sequence. $$a_{4}=e+2 \sqrt{\pi}, a_{5}=e+3 \sqrt{\pi}$$
View solution Problem 24
Write the binomial expansion for each expression. $$(m+n)^{4}$$
View solution Problem 24
Evaluate each expression. $$C(16,3)$$
View solution