Problem 24
Question
Find \(a_{8}\) and \(a_{n}\) for each arithmetic sequence. $$a_{4}=e+2 \sqrt{\pi}, a_{5}=e+3 \sqrt{\pi}$$
Step-by-Step Solution
Verified Answer
\(a_8 = e + 6\sqrt{\pi}\) and \(a_n = e + (n-2)\sqrt{\pi}\).
1Step 1: Identify Common Difference
In an arithmetic sequence, the difference between consecutive terms is constant. Here, the common difference \(d\) can be calculated as: \[ d = a_5 - a_4 = (e + 3 \sqrt{\pi}) - (e + 2 \sqrt{\pi}) = \sqrt{\pi}. \]
2Step 2: Use the Arithmetic Sequence Formula
The general formula for the \(n\)-th term of an arithmetic sequence is \(a_n = a_1 + (n-1)\cdot d\). However, since \(a_1\) is not directly given, we first determine \(a_1\) using the known terms by assuming a value for \(a_n\) such as \(a_4\).
3Step 3: Solve for \(a_1\)
Use the formula for the 4th term: \[ a_4 = a_1 + 3d = e + 2\sqrt{\pi}. \] Plugging in \(d = \sqrt{\pi}\), we get \[ a_1 + 3 \sqrt{\pi} = e + 2\sqrt{\pi}. \] Thus, \[ a_1 = e + 2\sqrt{\pi} - 3\sqrt{\pi} = e - \sqrt{\pi}. \]
4Step 4: Calculate \(a_8\)
Now that we have \(a_1 = e - \sqrt{\pi}\) and \(d = \sqrt{\pi}\), we can find \(a_8\) using the formula: \[ a_8 = a_1 + 7d = (e - \sqrt{\pi}) + 7 \cdot \sqrt{\pi} = e - \sqrt{\pi} + 7\sqrt{\pi} = e + 6\sqrt{\pi}. \]
5Step 5: Express the General Term \(a_n\)
Using \(a_1\) and \(d\), the general formula for the \(n\)-th term is: \[ a_n = a_1 + (n-1)\cdot d = (e - \sqrt{\pi}) + (n-1)\cdot \sqrt{\pi} = e + (n-2)\sqrt{\pi}. \]
Key Concepts
Common DifferenceArithmetic Sequence FormulaGeneral Term of a Sequence
Common Difference
The common difference is a fundamental component of arithmetic sequences. It's the consistent difference between consecutive terms, driving the sequence forward.
In the given example, the common difference \(d\) was identified between the 4th and 5th terms:
In the given example, the common difference \(d\) was identified between the 4th and 5th terms:
- \(a_4 = e + 2\sqrt{\pi}\)
- \(a_5 = e + 3\sqrt{\pi}\)
Arithmetic Sequence Formula
The arithmetic sequence formula is used to find any term in the sequence. It's typically expressed as:\[a_n = a_1 + (n-1) \cdot d\]where:
- \(a_n\) is the \(n\)-th term.
- \(a_1\) is the first term of the sequence.
- \(d\) is the common difference.
General Term of a Sequence
The general term of a sequence provides a handy way to express any term \(a_n\) in the sequence without needing explicit calculation for each term. With the equation \[a_n = a_1 + (n-1)\cdot d\] from the arithmetic sequence formula, every term can be found directly by modifying the term's index \(n\). By substituting \(a_1 = e - \sqrt{\pi}\) and \(d = \sqrt{\pi}\), we derived:\[a_n = (e - \sqrt{\pi}) + (n-1)\sqrt{\pi} = e + (n-2)\sqrt{\pi}.\] This expression allows quick reference to any term's value just by plugging the value of \(n\). Useful for arithmetic patterns, this method smoothens the understanding of sequence behavior and application.
Other exercises in this chapter
Problem 23
Evaluate each expression. $$C(12,4)$$
View solution Problem 23
Find the first four terms of each sequence. $$a_{1}=1, a_{2}=1, a_{n}=a_{n-1}+a_{n-2}, \text { for } n \geq 3$$ (the Fibonacci sequence)
View solution Problem 24
Use the formula for \(S_{n}\) to find the sum of the first five terms for each geometric sequence. Round the answers for Exercises 25 and 26 to the nearest hund
View solution Problem 24
Write the binomial expansion for each expression. $$(m+n)^{4}$$
View solution