Problem 24
Question
In Problems \(23-28,\) use the discriminant to identify the conic without actually graphing. $$ 2 x^{2}-2 x y+2 y^{2}=1 $$
Step-by-Step Solution
Verified Answer
The conic is an ellipse.
1Step 1: Identify Quadratic Form
First, let's identify the standard form of the given quadratic equation. The given equation is:\[ 2x^2 - 2xy + 2y^2 = 1 \]In the standard quadratic form for conic sections, it is given as:\[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]Here, \( A = 2 \), \( B = -2 \), \( C = 2 \), \( D = 0 \), \( E = 0 \), and \( F = -1 \).
2Step 2: Calculate the Discriminant
The discriminant for conic sections is calculated using the formula:\[ \Delta = B^2 - 4AC \]Substitute the values from the quadratic equation:\[ \Delta = (-2)^2 - 4(2)(2) \]\[ \Delta = 4 - 16 = -12 \]
3Step 3: Determine the Type of Conic
The value of the discriminant \( \Delta \) tells us the type of conic:- If \( \Delta > 0 \), the conic is a hyperbola.- If \( \Delta = 0 \), the conic is a parabola.- If \( \Delta < 0 \), the conic is an ellipse (or a circle if \( A = C \) and \( B = 0 \)).Since \( \Delta = -12 < 0 \), the conic is an ellipse.
Key Concepts
DiscriminantEllipseQuadratic Forms
Discriminant
The discriminant is a valuable tool in mathematics, particularly when dealing with conic sections. It helps us to identify the type of conic section represented by a given quadratic equation without having to graph it.
The discriminant for conic sections is derived from the general quadratic form and is calculated using the formula \( \Delta = B^2 - 4AC \). This formula stems from the coefficients of the quadratic equation, where \( A \), \( B \), and \( C \) are extracted.
Key points to remember about the discriminant in the context of conic sections:
The discriminant for conic sections is derived from the general quadratic form and is calculated using the formula \( \Delta = B^2 - 4AC \). This formula stems from the coefficients of the quadratic equation, where \( A \), \( B \), and \( C \) are extracted.
Key points to remember about the discriminant in the context of conic sections:
- If \( \Delta > 0 \), it indicates a hyperbola.
- If \( \Delta = 0 \), it signifies a parabola.
- If \( \Delta < 0 \), the resulting shape is an ellipse or, in special cases, a circle.
Ellipse
An ellipse is one of the four types of conic sections and is often defined by its oval shape. It is symmetric about its two principal axes.
Ellipses can be described in algebraic terms as an equation of the form \( Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \).
When dealing with the discriminant:
Ellipses can be described in algebraic terms as an equation of the form \( Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \).
When dealing with the discriminant:
- An ellipse is characterized by a discriminant \( \Delta < 0 \).
- If \( A = C \) and \( B = 0 \), the conic is a circle, which is a special type of ellipse.
Quadratic Forms
Quadratic forms are algebraic expressions involving squared terms. They are generally written as \( Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \). This standard form is essential when working with conics.
In the context of conic sections, the coefficients \( A \), \( B \), and \( C \) determine the shape and alignment of the conic.
To dissect a quadratic form:
In the context of conic sections, the coefficients \( A \), \( B \), and \( C \) determine the shape and alignment of the conic.
To dissect a quadratic form:
- Match each term with corresponding values like \( A \), \( B \), and \( C \).
- Utilize these coefficients to calculate the discriminant and ascertain the conic type.
- Observe that each type of conic section (ellipse, parabola, hyperbola) arises from different combinations of these coefficients.
Other exercises in this chapter
Problem 24
In Problems \(21-44,\) find an equation of the hyperbola that satisfies the given conditions. Foci \((0,\pm 3),\) one vertex \(\left(0,-\frac{3}{2}\right)\)
View solution Problem 24
Find an equation of the ellipse that satisfies the given conditions. Vertices \((0,\pm 7),\) foci (0,±3)
View solution Problem 24
Find the distance from the point (-6,2,-3) : (a) to the \(x_{Z}\) -plane (b) to the origin.
View solution Problem 24
Find the vertex, focus, directrix, and axis of the given parabola. Graph the parabola. \(3 x^{2}+30 x-8 y+75=0\)
View solution