Problem 24
Question
Find an equation of the ellipse that satisfies the given conditions. Vertices \((0,\pm 7),\) foci (0,±3)
Step-by-Step Solution
Verified Answer
The equation of the ellipse is \( \frac{x^2}{40} + \frac{y^2}{49} = 1 \).
1Step 1: Identify the Orientation of the Ellipse
The vertices of the ellipse are given as \(0, \pm 7\), and the foci are \(0, \pm 3\). Since both vertices and foci lie along the y-axis, the major axis is vertical.
2Step 2: Write the General Equation of the Vertical Ellipse
For a vertical orientation, the equation for an ellipse is \[\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1\]where \(a\) represents the semi-major axis, and \(b\) is the semi-minor axis.
3Step 3: Determine the Length of the Semi-Major Axis
The vertices \(0, \pm 7\) indicate that the length of the semi-major axis is \(a = 7\). Thus, \(a^2 = 49\).
4Step 4: Determine the Length of the Semi-Minor Axis Using the Foci
The foci \(0, \pm 3\) provide the value of \(c = 3\). In an ellipse, \(c^2 = a^2 - b^2\). Substitute the known values:\[3^2 = 7^2 - b^2\]\[9 = 49 - b^2\]\[b^2 = 40\]
5Step 5: Plug Values into the General Equation of the Ellipse
Now that we know \(a^2 = 49\) and \(b^2 = 40\), substitute these into the equation:\[\frac{x^2}{40} + \frac{y^2}{49} = 1\]
Key Concepts
Vertical EllipseSemi-Major AxisSemi-Minor AxisFoci of Ellipse
Vertical Ellipse
An ellipse with a vertical orientation is called a vertical ellipse. Understanding its characteristics is crucial when determining the equation of such an ellipse. This type of ellipse has its major axis aligned parallel to the y-axis.
- In a vertical ellipse, the largest distance across the shape, or the length of the major axis, runs vertically.
- The vertices (the furthest points on the ellipse from the center) are located on the line parallel to the y-axis.
Semi-Major Axis
The semi-major axis is one of the most important components in understanding an ellipse. It represents half the length of the major axis, which is the longest line segment that can be drawn through the center.
- For a vertical ellipse, the semi-major axis extends from the center to a vertex along the y-axis.
- The length of the semi-major axis is denoted as 'a'.
Semi-Minor Axis
Another crucial element of the ellipse is the semi-minor axis. This is the shorter distance across the ellipse, found perpendicular to the semi-major axis.
Given c = 3, inserting the known values into the formula allows us to solve for b^2: 3^2 = 7^2 - b^2 results in b^2 = 40. This value will be helpful in the final equation of the ellipse.
- For a vertical ellipse, the semi-minor axis stretches horizontally across the ellipse's center.
- The length of this axis is represented by 'b'.
Given c = 3, inserting the known values into the formula allows us to solve for b^2: 3^2 = 7^2 - b^2 results in b^2 = 40. This value will be helpful in the final equation of the ellipse.
Foci of Ellipse
The foci are unique points inside an ellipse that help in defining its shape. Every ellipse has two foci, and the sum of distances from any point on the ellipse to the foci is constant.
- For our vertical ellipse, these foci lie on the y-axis, as indicated by the coordinates (0, ± 3).
- The distance between the center of the ellipse and each focus is denoted by 'c'.
Other exercises in this chapter
Problem 23
Find the vertex, focus, directrix, and axis of the given parabola. Graph the parabola. \(6 y^{2}-12 y-24 x-42=0\)
View solution Problem 24
In Problems \(21-44,\) find an equation of the hyperbola that satisfies the given conditions. Foci \((0,\pm 3),\) one vertex \(\left(0,-\frac{3}{2}\right)\)
View solution Problem 24
In Problems \(23-28,\) use the discriminant to identify the conic without actually graphing. $$ 2 x^{2}-2 x y+2 y^{2}=1 $$
View solution Problem 24
Find the distance from the point (-6,2,-3) : (a) to the \(x_{Z}\) -plane (b) to the origin.
View solution