Problem 24
Question
Find a polynomial function \(P(x)\) having leading coefficient \(1,\) least possible degree, real coefficients, and the given zeros. $$-2+i,-2-i, 3, \text { and }-3$$
Step-by-Step Solution
Verified Answer
The polynomial is \(P(x) = x^4 + 4x^3 - 4x^2 - 36x - 45\).
1Step 1: Identify Zeros and Their Conjugates
The given zeros of the polynomial are complex and real: \(-2+i\), \(-2-i\), 3, and \(-3\). Since complex roots occur in conjugate pairs in polynomials with real coefficients, \(-2+i\) and \(-2-i\) are a conjugate pair and contribute to the polynomial.
2Step 2: Form Factor Pairs from Zeros
Create factors of the polynomial from each zero: For zero \(-2+i\), the factor is \((x - (-2+i)) = (x + 2 - i)\) and for \(-2-i\), it is \((x - (-2-i)) = (x + 2 + i)\). For zero 3, the factor is \((x - 3)\), and for zero -3, it is \((x + 3)\).
3Step 3: Form Polynomial from Complex Zeros
Multiply the complex conjugate pairs to simplify: \ \((x + 2 - i)(x + 2 + i) = (x + 2)^2 - i^2 = (x + 2)^2 + 1 = x^2 + 4x + 5\) (since \(i^2 = -1\)).
4Step 4: Combine All Factors into a Polynomial
Now multiply all factors together: \ \((x^2 + 4x + 5)(x - 3)(x + 3)\). Use the difference of squares: \ \((x^2 - 3^2) = (x^2 - 9)\).
5Step 5: Expand the Polynomial
Expand the polynomial by multiplying: \ \((x^2 + 4x + 5)(x^2 - 9)\). Use distributive property: \ First, \((x^2 + 4x + 5) \cdot x^2 = x^4 + 4x^3 + 5x^2\), \ Next, \((x^2 + 4x + 5) \cdot (-9) = -9x^2 - 36x - 45\). \ Then, combine: \ \(x^4 + 4x^3 + 5x^2 - 9x^2 - 36x - 45 = x^4 + 4x^3 - 4x^2 - 36x - 45\).
Key Concepts
Complex ConjugatesReal CoefficientsDifference of SquaresExpanding Polynomial
Complex Conjugates
In polynomial functions with real coefficients, complex roots always appear in pairs known as complex conjugates. This means that if a polynomial has a complex zero, such as
-2+i,
its conjugate,
-2-i,
will also be a zero. This pairing is essential because when these two roots are multiplied, the imaginary parts cancel out, ensuring the polynomial retains its real coefficients.
- The conjugate of a complex number a+bi is a-bi.
- By forming pairs like (x + 2 - i)(x + 2 + i), the result is a real quadratic factor.
Real Coefficients
Real coefficients in polynomials imply that each term of the polynomial is a real number. This is a common requirement, making them applicable to a wide range of real-world problems. When working with complex zeros, you need to ensure that they appear in conjugate pairs so that they combine to produce real factors.
This is seen in the step where
(x + 2 - i)
and
(x + 2 + i)
are multiplied, simplifying to
x^2 + 4x + 5.
Here, each term is real.
- When multiplying complex conjugates, the imaginary components cancel out.
- Ensure that polynomial equations maintain real coefficients by pairing conjugate roots.
Difference of Squares
The difference of squares is a handy algebraic identity that can simplify certain polynomial expressions. It is defined as
(a^2 - b^2) = (a - b)(a + b).
This identity is useful when dealing with polynomials that involve factors like
(x - 3)(x + 3).
Using the difference of squares allows us to quickly identify and simplify expressions obtained after pairing or expanding terms.
- The expression (x - 3)(x + 3) becomes (x^2 - 9), which is straightforward.
- This approach reduces complexity in polynomial expansion.
Expanding Polynomial
Expanding a polynomial involves multiplying the individual factors to form a single polynomial expression. This process transforms products of binomials and other expressions into a standard polynomial form. For example, after forming the simplified factors, the polynomial
(x^2 + 4x + 5)(x^2 - 9)
is expanded using the distributive property.
The key steps involve:
- Multiplying each term in the first polynomial by each term in the second polynomial.
- Using the distributive property to ensure all terms are accounted for and properly combined.
- Simplifying by combining like terms to form the final polynomial: x^4 + 4x^3 - 4x^2 - 36x - 45.
Other exercises in this chapter
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