Problem 23
Question
Solve each problem. Radius of a Can A can of garbanzo beans has surface. area 54.19 square inches. Its height is 4.25 inches. What is the radius of the circular top? See the figure. (Hint: The surface area consists of the circular top and bottom and a rectangle that represents the side cut open vertically and unrolled.) (IMAGE CAN'T COPY)
Step-by-Step Solution
Verified Answer
The radius of the can is approximately 2 inches.
1Step 1: Understand the Surface Area Formula for a Cylinder
The surface area of a cylinder consists of two circular bases and a lateral surface. The formula for the surface area of a cylinder is \( S = 2\pi r^2 + 2\pi rh \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.
2Step 2: Substitute the Given Values
Given that the total surface area, \( S \), is 54.19 square inches, and the height, \( h \), is 4.25 inches, substitute these values into the equation: \( 54.19 = 2\pi r^2 + 2\pi r(4.25) \).
3Step 3: Simplify and Solve for \( r \)
Simplify the equation to isolate \( r \): \( 54.19 = 2\pi r^2 + 8.5\pi r \). This is a quadratic equation in the form \( ax^2 + bx + c = 0 \), where \( a = 2\pi \), \( b = 8.5\pi \), and \( c = -54.19 \). Divide through by \( \pi \) to simplify: \( \frac{54.19}{\pi} = 2r^2 + 8.5r \).
4Step 4: Solve the Quadratic Equation
To solve for \( r \), use the quadratic formula \( r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 2 \), \( b = 8.5 \), and \( c = -\frac{54.19}{\pi} \). Calculate \( \Delta = b^2 - 4ac \) and substitute these into the quadratic formula to find \( r \).
5Step 5: Calculate \( \Delta \) and \( r \)
Calculate \( \Delta \) as follows: \( (8.5)^2 - 4\times2\times(-\frac{54.19}{\pi}) \) and use it to calculate the roots of the equation using the quadratic formula. Simplify to get the positive root since radius cannot be a negative value.
6Step 6: Verify the Solution
Confirm that the calculated radius satisfies the original surface area equation. Substituting \( r \) back into the simplified equation should approximately provide the total surface area of 54.19 square inches.
Key Concepts
Quadratic EquationCylinder GeometrySurface Area Formula
Quadratic Equation
A quadratic equation is a type of polynomial equation of degree two. It typically takes the form \[ ax^2 + bx + c = 0 \]where \( a eq 0 \). The unknown variable \( x \) can have two possible solutions, given that the equation represents a parabola that may intersect the \( x \)-axis at up to two points.
Here's how to understand a quadratic equation in the context of finding the radius of a cylinder:
Here's how to understand a quadratic equation in the context of finding the radius of a cylinder:
- The equation is set as \( 2\pi r^2 + 8.5\pi r = 54.19 \), where \( r \) is the radius of the cylinder.
- Identify \( a = 2\pi \), \( b = 8.5\pi \), and \( c = -54.19 \). These coefficients represent the parts of the quadratic equation related to the cylinder's dimensions.
- The quadratic formula is integral in solving these equations: \[ r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Cylinder Geometry
Understanding cylinder geometry is important to solve problems involving surface areas and volumes.A cylinder consists of two circular bases and a curved lateral surface connecting them.
In describing a cylinder:
In describing a cylinder:
- Radius \( r \): The distance from the center to the edge of the circular base.
- Height \( h \): The straight-line distance between the bases.
Surface Area Formula
The surface area of a cylinder is calculated using:\[ S = 2\pi r^2 + 2\pi rh \]where \( S \) represents total surface area, \( r \) is the radius of the base, and \( h \) is the height.This formula accounts for both the circular areas and the lateral surface area.
Here's the breakdown:
Here's the breakdown:
- Circular Bases: The term \( 2\pi r^2 \) calculates the total area of the two circles (top and bottom).
- Lateral Surface: The term \( 2\pi rh \) represents the area of the side of the cylinder, which can be visualized as a rectangle when unwrapped.
Other exercises in this chapter
Problem 23
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Write each number in simplest form, without a negative radicand. $$-\sqrt{-225}$$
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