Problem 23
Question
Write a balancedequation for the preparation of \(\mathrm{H}_{2}\) using (a) \(\mathrm{Mg}\) and an acid, (b) carbon and steam, (c) methane and steam.
Step-by-Step Solution
Verified Answer
The balanced chemical equations for the preparation of hydrogen gas using the given methods are:
(a) Mg + 2HCl → MgCl2 + H2
(b) C + H2O → CO + H2
(c) CH4 + H2O → CO + 3H2
1Step 1: (a) Writing the balanced equation for the preparation of hydrogen gas using magnesium and an acid
The unbalanced chemical equation for this reaction is:
Mg + HCl → MgCl2 + H2
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced chemical equation is:
Mg + 2HCl → MgCl2 + H2
2Step 2: (b) Writing the balanced equation for the preparation of hydrogen gas using carbon and steam
The unbalanced chemical equation for this reaction is:
C + H2O → CO + H2
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced chemical equation is:
C + H2O → CO + H2
3Step 3: (c) Writing the balanced equation for the preparation of hydrogen gas using methane and steam
The unbalanced chemical equation for this reaction is:
CH4 + H2O → CO + H2
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced chemical equation is:
CH4 + H2O → CO + 3H2
Key Concepts
Balanced EquationsHydrogen ProductionReaction Stoichiometry
Balanced Equations
Balanced equations are essential in chemical reactions. They show the reactants transforming into products while maintaining the law of conservation of mass. This law states that matter cannot be created or destroyed in a chemical reaction. Therefore, the number of atoms for each element must be the same on both sides of the equation. For instance, in the reaction of magnesium and hydrochloric acid to produce magnesium chloride and hydrogen gas, the unbalanced equation is:
Mg + HCl → MgCl2 + H2
Mg + HCl → MgCl2 + H2
- **Step 1:** Count the number of atoms of each element on both sides. Initially, we have 1 Mg, 1 Cl, and 2 H in the products, but only 1 Mg, 1 Cl, and 1 H in the reactants.
- **Step 2:** To balance, adjust the number of HCl molecules, resulting in: Mg + 2HCl → MgCl2 + H2.
- **Step 3:** Verify that each element is balanced: 1 Mg, 2 Cl, and 2 H on both sides.
Hydrogen Production
Hydrogen is a versatile element and a clean energy source. It can be produced through several chemical reactions. One common method is reacting magnesium with an acid, like hydrochloric acid, which results in hydrogen gas and a salt. Another method uses carbon and steam:
- **Reaction with Carbon and Steam**: Carbon reacts with water vapor to produce hydrogen gas and carbon monoxide. The balanced equation is:
C + H2O → CO + H2
This reaction is straightforward and illustrates the simplicity of hydrogen production using basic elements. Methane, the primary component of natural gas, can also produce hydrogen when reacted with steam:
- **Reaction with Methane and Steam**: Methane, when exposed to water vapor, yields carbon monoxide and hydrogen gas. The balanced equation for this is:
CH4 + H2O → CO + 3H2
Both processes are integral to industrial hydrogen production, highlighting the element's versatility and the efficiency of chemical reactions in generating useful compounds.
Reaction Stoichiometry
Reaction stoichiometry involves calculations based on balanced chemical equations. It helps determine the precise amount of reactants and products involved in a chemical reaction. For hydrogen production, understanding stoichiometry is crucial. Take the methane and steam reaction:
CH4 + H2O → CO + 3H2
Here, one molecule of methane reacts with one molecule of water to produce one molecule of carbon monoxide and three molecules of hydrogen gas. This ratio, derived from the balanced equation, lets chemists calculate:
CH4 + H2O → CO + 3H2
Here, one molecule of methane reacts with one molecule of water to produce one molecule of carbon monoxide and three molecules of hydrogen gas. This ratio, derived from the balanced equation, lets chemists calculate:
- **Moles to Moles:** If you start with 2 moles of methane, you'll get 6 moles of hydrogen gas.
- **Mass Calculations:** Using molar masses, you can convert between grams of methane and grams of hydrogen produced.
- **Limiting Reactants:** Identify which reactant runs out first, thereby limiting the amount of product formed.
Other exercises in this chapter
Problem 21
Give a reason why hydrogen might be placed along with the group 1 A elements of the periodic table.
View solution Problem 22
Why are the properties of hydrogen different from those of either the group \(1 \mathrm{~A}\) or \(7 \mathrm{~A}\) elements?
View solution Problem 24
List (a) three commercial means of producing \(\mathrm{H}_{2}\), (b) three industrial uses of \(\mathrm{H}_{2}\).
View solution Problem 25
Completeand balance the following equations: (a) \(\mathrm{NaH}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) (b) \(\mathrm{Fe}(s)+\mathrm{H}_{2} \mathrm{SO
View solution