Problem 23
Question
Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. $$ a=50, \quad b=100, \quad \angle A=50^{\circ} $$
Step-by-Step Solution
Verified Answer
No possible triangle satisfies the given conditions.
1Step 1: Identify the Formula
The Law of Sines is given by \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \). We will use this formula to solve for \( \angle B \) using the given values: \( a = 50 \), \( b = 100 \), and \( \angle A = 50^{\circ} \).
2Step 2: Plug Values into the Law of Sines
Using the Law of Sines: \( \frac{50}{\sin 50^{\circ}} = \frac{100}{\sin B} \). Rearrange to solve for \( \sin B \): \( \sin B = \frac{100 \cdot \sin 50^{\circ}}{50} \). Calculate further to find \( \sin B \).
3Step 3: Calculate \( \sin B \)
Calculate \( \sin B = 2 \cdot \sin 50^{\circ} \). Using a calculator, \( \sin 50^{\circ} \approx 0.7660 \). Thus, \( \sin B \approx 1.532 \). Since \( \sin B > 1 \), no triangle can have such an angle; check for special conditions.
4Step 4: Check for Ambiguity or No Solution
Since \( \sin B \) exceeds 1, it indicates no triangle can be formed to satisfy these conditions. Normally, when \( \sin B \approx 1 \) or greater, it’s a sign to reassess orientation or input; however, mathematically it's impossible to have an angle with \( \sin B > 1 \).
5Step 5: Conclusion: No Solution Possible
Given \( \sin B > 1 \), no valid angle for \( B \) exists, ruling out any real triangle formation under the provided constraints.
Key Concepts
TrianglesTrigonometric IdentitiesSolving Triangles
Triangles
Triangles are polygonal shapes that consist of three sides and three angles. They are fundamental in geometry and can be classified based on their side lengths or angle types.
- Equilateral Triangle - All three sides are equal in length, and each angle measures 60 degrees.
- Isosceles Triangle - Two sides are equal in length, and the angles opposite these sides are equal.
- Scalene Triangle - All sides and angles are different.
- Acute Triangle - All angles are less than 90 degrees.
- Right Triangle - One angle is exactly 90 degrees.
- Obtuse Triangle - One angle is greater than 90 degrees.
Trigonometric Identities
Trigonometric identities are equations that are true for all angles and are used to relate the angles and sides of a triangle. They are fundamental in solving triangles, particularly when dealing with the Law of Sines or the Law of Cosines.The Law of Sines is an important trigonometric identity given as:\[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\]Where:
Using trigonometric identities effectively is key to mastering triangle problems.
- is the side opposite angle A
- is the side opposite angle B
is the side opposite angle C
Using trigonometric identities effectively is key to mastering triangle problems.
Solving Triangles
Solving triangles involves calculating unknown sides or angles from the given information. Several rules can be applied depending on the known values:
Using the Law of Sines, for the scenario where:
- If two angles and one side are known, the remaining sides and angle can typically be solved using the Law of Sines.
- If two sides and one angle are known, you can use a combination of the Law of Sines and the Law of Cosines.
Using the Law of Sines, for the scenario where:
- a = 50
- b = 100
- \( \angle A = 50^{\circ} \)
Other exercises in this chapter
Problem 22
9–32 Find the exact value of the trigonometric function. $$\sin \frac{5 \pi}{3}$$
View solution Problem 22
Sketch a triangle that has acute angle \(\theta,\) and find the other five trigonometric ratios of \(\theta\). $$\csc \theta=\frac{13}{12}$$
View solution Problem 23
\(13-24\) . Find the degree measure of the angle with the given radian measure. $$ -\frac{2 \pi}{15} $$
View solution Problem 23
9–32 Find the exact value of the trigonometric function. $$\sin \frac{3 \pi}{2}$$
View solution