Problem 23
Question
9–32 Find the exact value of the trigonometric function. $$\sin \frac{3 \pi}{2}$$
Step-by-Step Solution
Verified Answer
\(\sin \frac{3\pi}{2} = -1\)
1Step 1: Understand the Unit Circle
The unit circle is a circle with a radius of 1 centered at the origin of a coordinate plane. It helps us find the sine and cosine values of angles. The coordinates of any point on the unit circle are given by \((\cos \theta, \sin \theta)\), where \(\theta\) is the angle.
2Step 2: Locate the Angle on the Unit Circle
The angle \(\frac{3\pi}{2}\) radians corresponds to 270 degrees. On the unit circle, this angle is located at the negative \(y\)-axis (straight down from the circle's center).
3Step 3: Determine the Sine Value
At \(270\) degrees or \(\frac{3\pi}{2}\) radians, the coordinate on the unit circle is \((0, -1)\). The sine of an angle in the unit circle is given by the \(y\)-coordinate of the point, which in this case is \(-1\).
4Step 4: Write the Exact Value
Using the point \((0, -1)\) on the unit circle, the sine function at \(\frac{3\pi}{2}\) is \(-1\). Therefore, the exact value of \(\sin \frac{3\pi}{2}\) is \(-1\).
Key Concepts
Unit CircleSine of an AngleRadian Measure
Unit Circle
The unit circle is a fundamental tool in trigonometry. It is a circle that has a radius of one, and its center is located at the origin (0,0) of a coordinate plane. The simplicity of the unit circle makes it easy to find the sine and cosine values of angles, as the x-coordinate represents the cosine, and the y-coordinate represents the sine.
In the unit circle, every angle can be represented as a point, and each point can be expressed in the form. These points make it incredibly straightforward to find exact trigonometric values without needing a calculator. For example:
In the unit circle, every angle can be represented as a point, and each point can be expressed in the form. These points make it incredibly straightforward to find exact trigonometric values without needing a calculator. For example:
- The angle of 0° or 0 radians is at the point (1, 0).
- The angle of 90° or \(\frac{\pi}{2}\) radians is at the point (0, 1).
- The angle of 180° or \(\pi\) radians corresponds to the point (-1, 0).
- The angle of 270° or \(\frac{3\pi}{2}\) radians is found at the point (0, -1).
Sine of an Angle
The sine of an angle is closely related to its position on the unit circle. Specifically, the sine value is the y-coordinate of the point where the terminal side of the angle intersects the unit circle. Understanding sine within this context helps you visualize and remember values easier.
When looking at the unit circle:
When looking at the unit circle:
- The sine of 0 is 0, because at the angle 0, the y-coordinate is 0.
- The sine of \(\frac{\pi}{2}\) is 1, as the point (0, 1) represents this angle, and the y-coordinate is 1.
- The sine of \(\pi\) is 0, because the coordinate at this angle is (-1, 0).
- The sine of \(\frac{3\pi}{2}\) is -1, where the point (0, -1) denotes the y-value.
Radian Measure
Radian measure is a way of measuring angles based on the radius of the circle. Unlike degrees, which divide a circle into 360 equal parts, radians use the circle's arc length relative to the radius.
One complete revolution around a circle equals 2\(\pi\) radians. This conversion is essential:
One complete revolution around a circle equals 2\(\pi\) radians. This conversion is essential:
- 90° is equivalent to \(\frac{\pi}{2}\) radians.
- 180° is equivalent to \(\pi\) radians.
- 270° is equivalent to \(\frac{3\pi}{2}\) radians.
- 360° is equivalent to 2\(\pi\) radians.
Other exercises in this chapter
Problem 23
Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. $$ a=50, \quad b=100, \quad \angle A=50^{\circ} $$
View solution Problem 23
\(13-24\) . Find the degree measure of the angle with the given radian measure. $$ -\frac{2 \pi}{15} $$
View solution Problem 23
Evaluate the expression without using a calculator. $$\sin \frac{\pi}{6}+\cos \frac{\pi}{6}$$
View solution Problem 24
Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. $$ a=100, \quad b=80, \quad \angle A=135^{\circ} $$
View solution