Problem 23
Question
Use the Binomial Theorcm to expand the expression. $$\left(1+\frac{1}{x}\right)^{6}$$
Step-by-Step Solution
Verified Answer
The expanded expression is \(1 + \frac{6}{x} + \frac{15}{x^2} + \frac{20}{x^3} + \frac{15}{x^4} + \frac{6}{x^5} + \frac{1}{x^6}\).
1Step 1: Understand Binomial Expansion Formula
The Binomial Theorem provides a way to expand expressions of the form \((a+b)^n\). Specifically, it states that \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\), where \(\binom{n}{k}\) is the binomial coefficient. Here, \(a = 1\), \(b = \frac{1}{x}\), and \(n = 6\).
2Step 2: Calculate Binomial Coefficients
The binomial coefficients are calculated using the formula \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\). We'll calculate these for each term in the expansion: - \(\binom{6}{0} = 1\),- \(\binom{6}{1} = 6\), - \(\binom{6}{2} = 15\), - \(\binom{6}{3} = 20\), - \(\binom{6}{4} = 15\), - \(\binom{6}{5} = 6\), - \(\binom{6}{6} = 1\).
3Step 3: Expand the Expression Using Binomial Coefficients
Using the values of \(a = 1\) and \(b = \frac{1}{x}\) and the binomial coefficients, expand the expression. The terms are:- \(\binom{6}{0}(1)^6\left(\frac{1}{x}\right)^0 = 1\),- \(\binom{6}{1}(1)^5\left(\frac{1}{x}\right)^1 = \frac{6}{x}\),- \(\binom{6}{2}(1)^4\left(\frac{1}{x}\right)^2 = \frac{15}{x^2}\),- \(\binom{6}{3}(1)^3\left(\frac{1}{x}\right)^3 = \frac{20}{x^3}\),- \(\binom{6}{4}(1)^2\left(\frac{1}{x}\right)^4 = \frac{15}{x^4}\),- \(\binom{6}{5}(1)^1\left(\frac{1}{x}\right)^5 = \frac{6}{x^5}\),- \(\binom{6}{6}(1)^0\left(\frac{1}{x}\right)^6 = \frac{1}{x^6}\).
4Step 4: Combine the Terms
Add all the terms calculated in the previous step to get the expanded expression:\[ 1 + \frac{6}{x} + \frac{15}{x^2} + \frac{20}{x^3} + \frac{15}{x^4} + \frac{6}{x^5} + \frac{1}{x^6} \].
Key Concepts
Binomial ExpansionBinomial CoefficientFactorials
Binomial Expansion
The binomial expansion is a way to express the power of a binomial, which is an expression composed of two terms, into a series of terms using the Binomial Theorem.The theorem offers a method to take any expression in the form \((a+b)^n\) and expand it into a sum of individual terms.Each term in the expansion consists of coefficients, powers of one of the terms, and decreasing powers of the second term from the binomial.
For example, an expression \( (1 + \frac{1}{x})^6 \) becomes a series of terms calculated using the formula:
For example, an expression \( (1 + \frac{1}{x})^6 \) becomes a series of terms calculated using the formula:
- \( (a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \)
Binomial Coefficient
Binomial coefficients are crucial components in the binomial expansion.They dictate the weight of each term in the expansion.These coefficients can be found using the formula:
For instance, when expanding \((1 + \frac{1}{x})^6\), the coefficients will be calculated for each term using this formula:
- \(\binom{n}{k} = \frac{n!}{k!(n-k)!} \)
For instance, when expanding \((1 + \frac{1}{x})^6\), the coefficients will be calculated for each term using this formula:
- \(\binom{6}{0} = 1\)
- \(\binom{6}{1} = 6\)
- \(\binom{6}{2} = 15\)
- \(\binom{6}{3} = 20\)
- \(\binom{6}{4} = 15\)
- \(\binom{6}{5} = 6\)
- \(\binom{6}{6} = 1\)
Factorials
Factorials are a key mathematical operation often encountered when working with binomial coefficients.They are denoted by an exclamation mark \(!\), and represent the product of all positive integers up to a specified number.In other words, the factorial of \(n\), written as \(n!\), is calculated as:
Using this operation is essential for finding the binomial coefficients, as seen in formulas like \(\binom{n}{k} = \frac{n!}{k!(n-k)!} \).Here is a small example of how factorials come into play:
- \(n! = n \times (n-1) \times (n-2) \times … \times 1\)
Using this operation is essential for finding the binomial coefficients, as seen in formulas like \(\binom{n}{k} = \frac{n!}{k!(n-k)!} \).Here is a small example of how factorials come into play:
- \(3! = 3 \times 2 \times 1 = 6\)
- \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\)
Other exercises in this chapter
Problem 22
Use a graphing calculator to do the following. (a) Find the first 10 terms of the sequence. (b) Graph the first 10 terms of the sequence. $$a_{n}=a_{n-1}-a_{n-2
View solution Problem 23
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$2,5,8,11, \dots$$
View solution Problem 23
Let \(a_{n+1}=3 a_{n}\) and \(a_{1}=5 .\) Show that \(a_{n}=5 \cdot 3^{n-1}\) for all natural numbers \(n\)
View solution Problem 23
Determine the common ratio, the fifth term, and the \(n\) th term of the geometric sequence. $$2,6,18,54, \dots$$
View solution