Problem 23
Question
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$2,5,8,11, \dots$$
Step-by-Step Solution
Verified Answer
The common difference is 3, the 5th term is 14, the nth term is \(3n-1\), and the 100th term is 299.
1Step 1: Identify the Common Difference
To find the common difference in an arithmetic sequence, subtract the first term from the second term. Here, the terms are 2, 5, 8, and 11. The common difference \(d\) is calculated as follows: \(d = 5 - 2 = 3\).
2Step 2: Calculate the Fifth Term
The formula for the nth term of an arithmetic sequence is \(a_n = a_1 + (n-1) imes d\). We need to find the 5th term \(a_5\). Substituting into the formula: \(a_5 = 2 + (5-1) imes 3 = 2 + 12 = 14\).
3Step 3: Derive the General Formula for the nth Term
Using the nth term formula, \(a_n = a_1 + (n-1) imes d\), where \(a_1 = 2\) and \(d = 3\), the general formula is: \(a_n = 2 + (n-1) imes 3\). Simplify it to: \(a_n = 3n - 1\).
4Step 4: Calculate the 100th Term
Using the nth term formula derived in Step 3, \(a_n = 3n - 1\), find the 100th term \(a_{100}\). Substitute \(n = 100\) into the equation: \(a_{100} = 3 imes 100 - 1 = 300 - 1 = 299\).
Key Concepts
Understanding the Common DifferenceDemystifying the nth Term FormulaCalculating the General Term
Understanding the Common Difference
In an arithmetic sequence, the common difference is the key to understanding how the sequence progresses. It is the constant difference between consecutive terms in the sequence. In simple terms, it's how much we "jump" from one number to the next.
For example, in the sequence given: 2, 5, 8, 11, ..., to find this common difference, you subtract the first term from the second term. Here it is calculated as follows:
For example, in the sequence given: 2, 5, 8, 11, ..., to find this common difference, you subtract the first term from the second term. Here it is calculated as follows:
- 5 - 2 = 3
Demystifying the nth Term Formula
The nth term formula in an arithmetic sequence lets you calculate any term in the sequence without listing all other terms. It is expressed as:
For instance, to find the fifth term using this sequence, plug the values into the formula:
- \(a_n = a_1 + (n-1) \times d \)
For instance, to find the fifth term using this sequence, plug the values into the formula:
- \(a_5 = 2 + (5-1) \times 3 = 14\)
Calculating the General Term
The general term of an arithmetic sequence provides a simple formula to solve for any term without having to go step-by-step. This helps in efficiently working with large sequences.
Using the sequence provided, we derived the general formula:
Using the sequence provided, we derived the general formula:
- \(a_n = 3n - 1\)
- \(a_{100} = 3 \times 100 - 1 = 299\)
Other exercises in this chapter
Problem 22
Show that \(100 n \leq n^{2}\) for all \(n \geq 100\)
View solution Problem 22
Use a graphing calculator to do the following. (a) Find the first 10 terms of the sequence. (b) Graph the first 10 terms of the sequence. $$a_{n}=a_{n-1}-a_{n-2
View solution Problem 23
Use the Binomial Theorcm to expand the expression. $$\left(1+\frac{1}{x}\right)^{6}$$
View solution Problem 23
Let \(a_{n+1}=3 a_{n}\) and \(a_{1}=5 .\) Show that \(a_{n}=5 \cdot 3^{n-1}\) for all natural numbers \(n\)
View solution