Problem 23
Question
Use intercepts and a checkpoint to graph each equation. $$6 x-9 y=18$$
Step-by-Step Solution
Verified Answer
The graph of the equation passing through the points X-intercept (3,0) and Y-intercept (0,-2). The point (1,1) is a checkpoint which does not satisfy the equation and therefore does not lie on the line.
1Step 1: Find the x-intercept
Let y=0, we substitute y=0 into the equation and solve for x to get the x-intercept. So, we get \(6x - 9*0 = 18\), simplifies to \(6x = 18\), and upon dividing by 6 from both sides we get x=3. So, our x-intercept is (3,0).
2Step 2: Find the y-intercept
Similarly, let x=0, then substitute x=0 into the equation and solve for y to find the y-intercept. Thus, \(6*0 - 9y = 18\), which simplifies to \(-9y = 18\), and upon dividing by -9 from both sides, we get y=-2. So, our y-intercept is (0,-2).
3Step 3: Choose a checkpoint
Now, we choose a point not on the line made by the intercepts (i.e., neither (3,0) nor (0,-2)). The point (1,1) is a simple choice. Substituting x=1 and y=1 into the equation, we have \(6*1 - 9*1 = -3\), which is not equal to 18. Hence this point (1,1) does not lie on the line.
4Step 4: Graph the equation
Using the x and y intercepts (3,0) and (0,-2), we plot these points on the graph. Then draw a line passing through the intercept points to represent the equation.
Key Concepts
X-InterceptY-InterceptAlgebraic GraphingLinear Equations
X-Intercept
The x-intercept of a graph is where the line crosses the x-axis. To find it, you set the y-coordinate to 0 and solve the equation for x. In the equation
When practicing with x-intercepts, always remember:
6x - 9y = 18, when we set y = 0, it simplifies to 6x = 18. Dividing both sides by 6 gives us x = 3, so the x-intercept is (3,0). This is a pivotal point since it establishes where the line begins on the horizontal axis.When practicing with x-intercepts, always remember:
- Set y to zero before solving for x.
- The resulting point will always have the form (x,0).
Y-Intercept
In contrast to the x-intercept, the y-intercept is where a line crosses the y-axis. Here, you'll set the x-coordinate to 0 and solve for y. Taking our earlier example,
The y-intercept is equally important as the x-intercept because it marks the start of the line on the vertical axis. Keep in mind to:
6x - 9y = 18, and setting x = 0 we get -9y = 18. Dividing both sides by -9, the solution is y = -2, which gives us the y-intercept as (0,-2).The y-intercept is equally important as the x-intercept because it marks the start of the line on the vertical axis. Keep in mind to:
- Set x to zero before finding y.
- The point obtained will have a (0,y) form.
Algebraic Graphing
Moving forward, algebraic graphing is a technique used to visually represent solutions of equations on a coordinate plane. Once we have our x and y-intercepts from the equation
For algebraic graphing, following these steps ensures accurate representation:
6x-9y=18, we plot these points on a Cartesian plane.For algebraic graphing, following these steps ensures accurate representation:
- Plot the x-intercept and y-intercept accurately on the graph.
- Use a straightedge to draw a line through these intercepts, which is your linear equation.
- If necessary, select an additional 'checkpoint' outside the intercepts to ensure the line is correct.
Linear Equations
Lastly, let's talk about linear equations. These equations form straight lines when graphed and typically look like
Key points to note about linear equations include:
ax + by = c, where a, b, and c are constants. They have a constant rate of change and no variable is raised to a power other than 1. By finding the x-intercept and y-intercept, you have all the necessary information to draw the line.Key points to note about linear equations include:
- They produce straight lines on a graph.
- The slope-intercept form,
y = mx + b, reveals the slope (m) and y-intercept (b) directly, which can also be useful in graphing the line quickly.
6x - 9y = 18 is a classic linear equation and provides a straightforward example of how linear relationships are visually represented in graphing.Other exercises in this chapter
Problem 23
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