Problem 23
Question
In Exercises \(13-26,\) begin by solving the linear equation for \(y .\) This will put the equation in slope-intercept form. Then find the slope and the \(y\) -intercept of the line with this equation. $$3 x+2 y=3$$
Step-by-Step Solution
Verified Answer
The slope is \(-\frac{3}{2}\) and the y-intercept is \frac{3}{2}.
1Step 1: Convert to slope-intercept form
Begin by subtracting \(3x\) from both sides of the equation \(3x + 2y = 3\) to isolate \(2y\). This gives us \(2y = -3x + 3\). Then, divide the entire equation by \(2\) to solve for \(y\). This gives us \(y = -\frac{3x}{2} + \frac{3}{2}\). The equation is now in the form \(y = mx + b\).
2Step 2: Identify the Slope
The slope \(m\) is the coefficient of \(x\) in the equation \(y = mx + b\). Looking at our equation \(y = -\frac{3x}{2} + \frac{3}{2}\), the slope \(m\) is \(-\frac{3}{2}\).
3Step 3: Identify the y-intercept
The \(y\)-intercept \(b\) is the constant in the equation \(y = mx + b\). Looking at our equation \(y = -\frac{3x}{2} + \frac{3}{2}\), the \(y\)-intercept \(b\) is \frac{3}{2}.
Key Concepts
Slope-Intercept FormSolving for yIdentifying Slope and Intercept
Slope-Intercept Form
The slope-intercept form of a linear equation is one of the most popular ways to express a linear equation. It is written as \( y = mx + b \), where:
To convert a linear equation into this form, you need to solve the equation for \( y \). This involves isolating \( y \) on one side of the equation. By doing this, you can easily identify the slope and intercept from the resulting equation.
- \( y \) represents the dependent variable
- \( m \) is the slope of the line
- \( x \) is the independent variable
- \( b \) is the y-intercept
To convert a linear equation into this form, you need to solve the equation for \( y \). This involves isolating \( y \) on one side of the equation. By doing this, you can easily identify the slope and intercept from the resulting equation.
Solving for y
To put a linear equation into slope-intercept form, we must first solve for \( y \). Starting with an equation like \( 3x + 2y = 3 \), the goal is to isolate \( y \):
Remember, the process involves both operations of addition or subtraction to remove terms from one side, and division to adjust the coefficient of \( y \) to be 1.
- Start by moving terms involving \( x \) to the other side of the equation: \( 2y = -3x + 3 \)
- Next, divide each term by the coefficient in front of \( y \) to solve for \( y \). In our example, divide by 2: \( y = -\frac{3}{2}x + \frac{3}{2} \)
Remember, the process involves both operations of addition or subtraction to remove terms from one side, and division to adjust the coefficient of \( y \) to be 1.
Identifying Slope and Intercept
Once the linear equation is in the slope-intercept form \( y = mx + b \), finding the slope and y-intercept is simple:
Understanding both the slope and intercept helps predict and visualize how a line behaves on a graph.
- The slope \( m \) is the coefficient of \( x \). In \( y = -\frac{3}{2}x + \frac{3}{2} \), the slope \( m \) is \(-\frac{3}{2}\).
- The y-intercept \( b \) is the constant value. For \( y = -\frac{3}{2}x + \frac{3}{2} \), the y-intercept \( b \) is \(\frac{3}{2}\).
Understanding both the slope and intercept helps predict and visualize how a line behaves on a graph.
Other exercises in this chapter
Problem 22
Plot the given point in a rectangular coordinate system. $$\left(-\frac{5}{2}, 0\right)$$
View solution Problem 23
Write the point-slope form of the equation of the line satisfying each of the conditions in Exercises \(1-28 .\) Then use the point-slope form of the equation t
View solution Problem 23
Determine whether the distinct lines through each pair of points are parallel. $$(-2,0)\( and \)(0,6) ;(1,8)\( and \)(0,5)$$
View solution Problem 23
Use intercepts and a checkpoint to graph each equation. $$6 x-9 y=18$$
View solution