Problem 23
Question
Simplify each polynomial and write it in descending powers of one variable. $$ \frac{1}{2} s t+\frac{3}{2} s t $$
Step-by-Step Solution
Verified Answer
The simplified polynomial is \( 2st \).
1Step 1: Identify Identical Terms
The given expression is \( \frac{1}{2} s t + \frac{3}{2} s t \). Both terms, \( \frac{1}{2} s t \) and \( \frac{3}{2} s t \), contain the same variables \( s \) and \( t \) raised to the same power, hence they are like terms.
2Step 2: Add Coefficients of Like Terms
Add the coefficients of the like terms: \( \frac{1}{2} \) and \( \frac{3}{2} \). This gives us \( \frac{1}{2} + \frac{3}{2} = \frac{4}{2} \).
3Step 3: Simplify the Coefficient
Simplify the fraction \( \frac{4}{2} \). This simplifies to \( 2 \).
4Step 4: Write the Polynomial in Descending Powers
With the simplified coefficient, write the polynomial as \( 2 s t \). Here, the polynomial is already in descending order in terms of any variable \( s \) or \( t \) which have the same degree.
Key Concepts
Like TermsCoefficient AdditionDescending Power Order
Like Terms
When simplifying polynomials, identifying 'like terms' is essential. Like terms are terms that involve the same variables raised to the same powers. This equivalency allows them to be combined. For instance, in the term \( \frac{1}{2} s t + \frac{3}{2} s t \), both parts contain the variables \( s \) and \( t \), each raised to the first power. Hence, these are like terms. Identifying like terms helps to streamline complex expressions, making them much easier to manipulate and simplify. Since polynomials can include numerous terms, spotting these common variables is a key step in polynomial operations.
Coefficient Addition
In polynomial simplification, after identifying like terms, the next step is coefficient addition. Coefficients are the numerical parts in front of any variables. Adding these together helps simplify the expression further.
For example, in the expression \( \frac{1}{2} s t + \frac{3}{2} s t \), you would add the coefficients directly: \( \frac{1}{2} + \frac{3}{2} = \frac{4}{2} \).
Once added, simplify the resulting number. Here, \( \frac{4}{2} \) simplifies to \( 2 \). Thus, the expression becomes \( 2s t \).
For example, in the expression \( \frac{1}{2} s t + \frac{3}{2} s t \), you would add the coefficients directly: \( \frac{1}{2} + \frac{3}{2} = \frac{4}{2} \).
Once added, simplify the resulting number. Here, \( \frac{4}{2} \) simplifies to \( 2 \). Thus, the expression becomes \( 2s t \).
- Always ensure the variables and powers align before adding coefficients.
- This step condenses terms to make handling them easier.
Descending Power Order
Writing a polynomial in descending power order is another essential step. This involves arranging terms based on the powers of a key variable, generally starting from the highest to the lowest. It helps in maintaining a standard form that math users recognize and utilize.
- In our expression \( 2 s t \), deciding on descending order is simple as both the \( s \) and \( t \) have the same powers.
- This enables the polynomial to stay neatly organized.
Other exercises in this chapter
Problem 23
Multiply. See Example 1. $$ \left(8 a^{5}\right)\left(-\frac{1}{4} a^{6}\right) $$
View solution Problem 23
Write each expression in an equivalent form using an exponent. $$ \frac{t}{2} \cdot \frac{t}{2} \cdot \frac{t}{2} $$
View solution Problem 23
Convert number to standard notation. \(2.718 \times 10^{0}\)
View solution Problem 23
Express using positive exponents and simplify, if possible. \(6^{-1}\)
View solution