Problem 23
Question
Multiply. See Example 1. $$ \left(8 a^{5}\right)\left(-\frac{1}{4} a^{6}\right) $$
Step-by-Step Solution
Verified Answer
The result of multiplying \((8a^5)\) and \((-\frac{1}{4}a^6)\) is \(-2a^{11}\).
1Step 1: Identify the Components
First, identify the parts inside the given expression to understand what is being multiplied. You have two terms: \(8a^{5}\) and \(-\frac{1}{4}a^{6}\). These contain coefficients (8 and \(-\frac{1}{4}\)) and variables with exponents \(a^{5}\) and \(a^{6}\).
2Step 2: Multiply the Coefficients
Multiply the numerical coefficients of the two terms. Simplify: \(8\times -\frac{1}{4}\). This equals \(-2\) (since \(8 \times -\frac{1}{4} = -2\)).
3Step 3: Apply the Product Rule to Exponents
Multiply the variables with exponents using the product rule for exponents, which states that \(a^{m} \times a^{n} = a^{m+n}\). For the expression, multiply \(a^{5}\) and \(a^{6}\) as follows: \(a^{5+6} = a^{11}\).
4Step 4: Combine the Results
Now, combine the results from Steps 2 and 3. The product of the coefficients is \(-2\) and the product of the variables is \(a^{11}\), giving the final expression: \(-2a^{11}\).
Key Concepts
CoefficientsExponentsProduct Rule
Coefficients
When dealing with algebraic multiplication, coefficients play a crucial role. In mathematical expressions, a coefficient is the numerical factor that multiplies a variable. In the expression \(8a^5\), the number 8 is the coefficient of the variable \(a^5\). Likewise, in \(-\frac{1}{4}a^6\), the coefficient is \(-\frac{1}{4}\). This shows the constant proportionality each term has to the variable involved.When multiplying two expressions, you start by multiplying their coefficients. This is done just like you would in regular arithmetic. For instance, to multiply the coefficients 8 and \(-\frac{1}{4}\), you simply perform the multiplication:
- 8 times \(-\frac{1}{4}\) equals \(-2\).
Exponents
In algebra, exponents denote how many times a number, known as the base, is multiplied by itself. When considering the expression \(a^5\), the 5 is the exponent, and it tells us that the base \(a\) is used as a factor five times in multiplication. Similarly, the term \(a^6\) means that \(a\) is repeated six times as a factor.Exponents are particularly useful when multiplying terms with the same base. This is because there is a specific rule that governs their multiplication:
- When you multiply two powers with the same base, you add their exponents.
- The exponents are added: \(5 + 6 = 11\).
Product Rule
The product rule for exponents simplifies the process of multiplying exponential terms. It is an essential algebraic rule that states: when multiplying two powers with the same base, you add the exponents. This rule applies when you encounter terms like \(a^m \times a^n\).Here's how it works:
- Assume you have \(a^5\) and \(a^6\).
- The product rule says you should add the exponents: \(5 + 6\).
- The result is \(a^{11}\), which summarizes the original multiplication in a compact form.
Other exercises in this chapter
Problem 22
Convert number to standard notation. \(9.998 \times 10^{5}\)
View solution Problem 22
Express using positive exponents and simplify, if possible. \(7^{-2}\)
View solution Problem 23
Write each expression in an equivalent form using an exponent. $$ \frac{t}{2} \cdot \frac{t}{2} \cdot \frac{t}{2} $$
View solution Problem 23
Simplify each polynomial and write it in descending powers of one variable. $$ \frac{1}{2} s t+\frac{3}{2} s t $$
View solution