Problem 23
Question
In Exercises 9-50, verify the identity \( \dfrac{\cot x}{\sec x} = \csc x - \sin x \)
Step-by-Step Solution
Verified Answer
After breaking down Cotangent, Secant and Cosecant into terms of Sine and Cosine and performing the correct substitution, it is confirmed that \( \dfrac{\cot x}{\sec x} = \csc x - \sin x \), so the given identity holds true.
1Step 1: Break down Cotangent and Secant into terms of Sine and Cosine
The given identity is \( \dfrac{\cot x}{\sec x} = \csc x - \sin x \). Let's break down the left side into more fundamental trigonometric functions. So, \( \cot x = \dfrac{\cos x}{\sin x} \) and \( \sec x = \dfrac{1}{\cos x} \). Hence, the left side becomes \( \dfrac{\dfrac{\cos x}{\sin x}}{\dfrac{1}{\cos x}} \).
2Step 2: Simplify Left Hand Side
Simplify the above expression by multiplying the numerator and the denominator by \( \cos x \). We get \( \dfrac{\cos^2 x}{\sin x} \). Now we know that \( \cos^2 x = 1 -\sin^2 x \), so we can replace \( \cos^2 x \) with \( 1 -\sin^2 x \). Now the expression becomes \( \dfrac{1 -\sin^2 x}{\sin x} \). We can break this down to: \( \dfrac{1}{\sin x} - \sin x \).
3Step 3: Recognize Cosecant and Simplify
The step from here to the right hand side is to recognize that \( \dfrac{1}{\sin x} = \csc x \). So we substitute \( \dfrac{1}{\sin x} \) with \( \csc x \) and simplify the expression. This will give us \( \csc x - \sin x \) which is equal to the right hand side of the given identity. Hence, the given identity \( \dfrac{\cot x}{\sec x} = \csc x - \sin x \) is indeed true.
Key Concepts
CotangentSecantCosecant
Cotangent
Cotangent is one of the six primary trigonometric functions. It is often abbreviated as "cot" and is defined as the reciprocal of the tangent function. The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side. Therefore, the cotangent of an angle is given by the formula:
Recognizing the reciprocal relationships between trigonometric functions is crucial. For example, knowing that \( \cot x = \dfrac{1}{\tan x} \), helps us easily transform and manipulate expressions involving cotangent.
- \(\cot x = \dfrac{1}{\tan x} = \dfrac{\cos x}{\sin x}\)
Recognizing the reciprocal relationships between trigonometric functions is crucial. For example, knowing that \( \cot x = \dfrac{1}{\tan x} \), helps us easily transform and manipulate expressions involving cotangent.
Secant
The secant function, abbreviated as "sec," is another essential trigonometric function. It is the reciprocal of the cosine function. In a right triangle, the cosine of an angle is the ratio of the adjacent side to the hypotenuse. Hence, secant is defined as:
For example, in our exercise, transforming the expression \( \dfrac{\cot x}{\sec x} \) required us to break down our functions into sine and cosine terms. By doing so, it simplifies the process of verifying or solving trigonometric identities.
- \(\sec x = \dfrac{1}{\cos x}\)
For example, in our exercise, transforming the expression \( \dfrac{\cot x}{\sec x} \) required us to break down our functions into sine and cosine terms. By doing so, it simplifies the process of verifying or solving trigonometric identities.
Cosecant
Cosecant is the last of the three reciprocal trigonometric functions we will discuss. Often abbreviated as "csc," it is the reciprocal of the sine function. In a right triangle, the sine is the ratio of the opposite side to the hypotenuse. Therefore, the cosecant is:
Cosecant often appears in identities and expressions alongside other functions, facilitating simplification. In the identity we verified, recognizing that \( \dfrac{1}{\sin x} = \csc x \) was key in confirming that the left and right sides of the equation matched. This highlights the role of reciprocal identities in solving trigonometric problems.
- \(\csc x = \dfrac{1}{\sin x}\)
Cosecant often appears in identities and expressions alongside other functions, facilitating simplification. In the identity we verified, recognizing that \( \dfrac{1}{\sin x} = \csc x \) was key in confirming that the left and right sides of the equation matched. This highlights the role of reciprocal identities in solving trigonometric problems.
Other exercises in this chapter
Problem 23
In Exercises 13 - 28, find the exact values of the sine, cosine, and tangent of the angle. $ -\dfrac{13\pi}{12}
View solution Problem 23
In Exercises 11-24, solve the equation. \( \tan 3x (\tan x - 1) = 0 \)
View solution Problem 23
In Exercises 11 - 24, use the given values to evaluate (if possible)all six trigonometric functions. \( \sin \theta = -1 \), \( \cot \theta = 0 \)
View solution Problem 24
In Exercises 19-28, find the exact solutions of the equation in the interval \( [0, 2\pi) \). \( \cos 2x + \sin x = 0 \)
View solution